sql子查询返回“每个派生表必须有自己的别名”

Question

我在服务器中执行了此查询并获得了

$query1="select clients.name AS client,
packages.pick AS pick,
packages.drop AS `drop`,
packages.created AS created,
packages.status AS status,
packages.id AS id,
packages.name AS package
 from  (packages join clients on(clients.id = packages.client_id))";

$result = $mysqli->query("select count(*) as num from ($query1)");

我得到了上述错误，知道导致错误的原因是什么？

Answer 1

要命名子查询：

from ($query1) as SubQueryAlias