Question

我有一张这样的桌子......

oid      id 
35       1  
43       1  
46       1 
43       2  
49       2

我有 id = 1 现在我想要那些只属于1而不属于任何其他ID的记录。

即o / p - 35,46

我不需要oid = 43 bcz它也属于2。

我不知道如何在stackoverflow上的表格中写下我的问题所以请忽略我错误的询问方式。

感谢

Answer 1

尝试以下：

SELECT * FROM `table`
WHERE id = 1 AND oid NOT IN (SELECT oid FROM `table` where id != 1)

Answer 2

这是另一种方式，

SELECT  oid
FROM    tableName
GROUP   BY oid
HAVING  COUNT(DISTINCT id) = 1 AND  -- counts the number of ID for OID
        MAX(ID) = 1                 -- checks if the value of ID is equal to 1

SQLFiddle Demo

输出

╔═════╗
║ OID ║
╠═════╣
║  35 ║
║  46 ║
╚═════╝

Answer 3

select count(oid), oid from table
where id = 1
group by oid
having count(oid) = 1

Answer 4

SELECT * 
FROM TABLE_NAME
WHERE id = 1 
AND oid NOT IN (SELECT DISTINCT oid FROM TABLE_NAME where id != 1)

仅获取单个id的记录，而不是其他任何记录

4 个答案: