Question

我正在使用本教程：http://www.androidhive.info/2012/10/android-multilevel-listview-tutorial/

在这里他创造了3种不同的JSON，

首先，以获取相册列表

第二次，以获取相册

下的歌曲列表

第三次，以显示单曲信息

但我需要在这里做一个小改动，而不是3种不同的JSON ，我想要使用单个JSON用于两个专辑＆amp;歌曲，我也创建了我的演示JSON，我能够获得专辑列表但没有获得歌曲列表，我的JSON看起来像这样，我使用相同的代码正如他为客户端撰写的那样：

my.json：

[
{
    "id": 1,
    "name": "127 Hours",
    "album": "127 Hours",
    "songs": [
        {
            "id": 1,
            "name": "Never Hear Surf Music Again",
            "duration": "5:52"
        },
        {
            "id": 2,
            "name": "The Canyon",
            "duration": "3:01"
        }
    ]
}
]

logcat的：

06-18 06:36:56.318: D/dalvikvm(793): GC_CONCURRENT freed 143K, 7% free 3745K/4012K, paused 6ms+127ms, total 243ms
06-18 06:36:56.399: I/Choreographer(793): Skipped 37 frames!  The application may be doing too much work on its main thread.
06-18 06:36:56.689: I/Choreographer(793): Skipped 66 frames!  The application may be doing too much work on its main thread.
06-18 06:36:57.508: D/Track List JSON:(793): [
06-18 06:36:57.508: D/Track List JSON:(793): {
06-18 06:36:57.508: D/Track List JSON:(793): "id":1,
06-18 06:36:57.508: D/Track List JSON:(793): "name":"127 Hours",
06-18 06:36:57.508: D/Track List JSON:(793): "album":"127 Hours",
06-18 06:36:57.508: D/Track List JSON:(793): "songs":[
06-18 06:36:57.508: D/Track List JSON:(793): {
06-18 06:36:57.508: D/Track List JSON:(793): "id":1,
06-18 06:36:57.508: D/Track List JSON:(793): "name":"Never Hear Surf Music Again",
06-18 06:36:57.508: D/Track List JSON:(793): "duration":"5:52"
06-18 06:36:57.508: D/Track List JSON:(793): },
06-18 06:36:57.508: D/Track List JSON:(793): {
06-18 06:36:57.508: D/Track List JSON:(793): "id":2,
06-18 06:36:57.508: D/Track List JSON:(793): "name":"The Canyon",
06-18 06:36:57.508: D/Track List JSON:(793): "duration":"3:01"
06-18 06:36:57.508: D/Track List JSON:(793): }
06-18 06:36:57.508: D/Track List JSON:(793): ]
06-18 06:36:57.508: D/Track List JSON:(793): }
06-18 06:36:57.508: D/Track List JSON:(793): ]
06-18 06:36:57.668: W/System.err(793): org.json.JSONException: Value [{"id":1,"songs":[{"id":1,"duration":"5:52","name":"Never Hear Surf Music Again"},{"id":2,"duration":"3:01","name":"The Canyon"}],"album":"127 Hours","name":"127 Hours"}] of type org.json.JSONArray cannot be converted to JSONObject
06-18 06:36:57.668: W/System.err(793):  at org.json.JSON.typeMismatch(JSON.java:111)
06-18 06:36:57.668: W/System.err(793):  at org.json.JSONObject.<init>(JSONObject.java:158)
06-18 06:36:57.788: W/System.err(793):  at org.json.JSONObject.<init>(JSONObject.java:171)
06-18 06:36:57.888: W/System.err(793):  at com.example.androidhive.TrackListActivity$LoadTracks.doInBackground(TrackListActivity.java:155)
06-18 06:36:57.898: W/System.err(793):  at com.example.androidhive.TrackListActivity$LoadTracks.doInBackground(TrackListActivity.java:1)
06-18 06:36:57.898: W/System.err(793):  at android.os.AsyncTask$2.call(AsyncTask.java:287)
06-18 06:36:57.898: W/System.err(793):  at java.util.concurrent.FutureTask.run(FutureTask.java:234)
06-18 06:36:57.898: W/System.err(793):  at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1080)
06-18 06:36:57.898: W/System.err(793):  at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:573)
06-18 06:36:57.909: W/System.err(793):  at java.lang.Thread.run(Thread.java:856)

注意：我可以获取相册列表，但每当我点击任何相册都没有收到歌曲

Answer 1

因为你的json数据以方括号开头意味着它是一个jsonarray，你需要用jsonarray开始解析它。

此代码可以帮助您..

JSONArray array = new JSONArray("Your_json_string");
 for(int i=0;i<array.length();i++){
     System.out.println("id:"+array.getJSONObject(i).getString("id"));
     System.out.println("name:"+array.getJSONObject(i).getString("name"));
     System.out.println("album:"+array.getJSONObject(i).getString("album"));
     JSONArray innerArray = getJSONObject(i)..getJSONArray("songs");
      for(int k=0;k<innerArray.length();k++){
        JsonObject innerObj = innerArray.getJSONObject(k);
         System.out.println("id:"+innerObj.getString("id"));
         System.out.println("Name:"+innerObj.getString("name"));
          System.out.println("duration:"+innerObj.getString("duration"));          

      }
    }

Answer 2

您正在尝试将JSON数组转换为JSON对象，这就是问题所在。

org.json.JSONException: Value [.......] of type org.json.JSONArray cannot be converted to JSONObject

下面：

JSONObject jObj = new JSONObject(json);

您的JSON字符串实际上是一个数组，而不是一个对象，因为它以[]开头。

如果您想要处理一个对象，请更改它并使其以{}开头，并且您已完成（或将其转换为JSONArray并获得第一个值）！

编辑：

这应该有效：

{
    "id": 1,
    "name": "127 Hours",
    "album": "127 Hours",
    "songs": [
        {
            "id": 1,
            "name": "Never Hear Surf Music Again",
            "duration": "5:52"
        },
        {
            "id": 2,
            "name": "The Canyon",
            "duration": "3:01"
        }
    ]
}

单个JSON以获取多个记录

2 个答案: