我正在编写一个扫雷游戏,我正在尝试使用一个哈希集。我的问题是,hashset是否包含整数和字符串?我使用的hastset主要是字符串,一个是整数。可以这样做吗?当我编译它时,它给我一个错误,即无法找到变量_minecount,没有关于它不是一个字符串。这是我的代码:
import java.util.Set;
import java.util.HashSet;
/**
* Represents a single square in Minesweeper.
*
* @author Sophia Ali
*/
public class MineSquare
{
//Constants:
// Fields:
private String _shown; // What a square is showing now
private boolean _mined; // Square is mined or not
private boolean _flagged; // Square is flagged or not
private boolean _questioned; // Square is question marked or not
private int _minecount; // Square's surrounding mine count
private boolean _opened; // Player has opened this square or not
private static final String[] VALID_SHOWN_TEXT = {"X", 0 < minecount && _minecount < 8, " ", "F", "?"};
private HashSet<String> validShownTextSet =
new HashSet<String>(java.util.Arrays.asList(VALID_SHOWN_TEXT));
// Constructors & Methods:
/**
* Default constructor
* Sets _mined and _opened to false.
*/
public MineSquare()
{
_mined = false;
_opened = false;
setShown(" ");
}
/**
* Returns flagged status of square.
* @return _flagged Flagged status
*/
public boolean isFlagged() {
return _flagged;
}
/**
* Sets or unsets flag on a square.
* @param flagged True or false (square is flagged or not)
*/
public void setFlagged(boolean flagged, boolean opened) {
_flagged = flagged;
_opened = opened;
// If Minesquare opened do nothing:
if (opened == true)
setShown(" ");
// If flagged, square should show "F":
if ( isFlagged() == true )
setShown("F");
else
setShown(" ");
}
public int getMinecount() {
return _minecount;
}
public void setMinecount(int minecount) {
_minecount = minecount;
if ( 0 < minecount && minecount < 8 )
{
setShown("Error:" + minecount);
}
}
public boolean isMined() {
return _mined;
}
public void setMined(boolean mined) {
_mined = mined;
}
public boolean isOpened() {
return _opened;
}
/**
* Open a square.
* (Once opened, a square can't be unopened.)
*/
public void setOpened() {
_opened = true;
if ( isMined() == true )
setShown("X");
else if ( getMinecount() > 0 )
setShown(_minecount + "");
else // blank space for _minecount = 0
setShown(" ");
}
public boolean isQuestioned() {
return _questioned;
}
public void setQuestioned(boolean questioned, boolean opened) {
_questioned = questioned;
_opened = opened;
// If Minesquare opened do nothing:
if (opened == true)
setShown(" ");
// If Questioned, square should show "F":
if ( isQuestioned() == true )
setShown("F");
else
setShown(" ");
}
public String getShown() {
return _shown;
}
public void setShown(String shown) {
_shown = shown;
/*if (shown.equals("X")) {
this.shown = shown;
} else if (shown.equals( 0 < minecount && minecount < 8 )) {
this.shown = shown;
} else if (shown.equals(" ")) {
this.shown = shown;
} else if (shown.equals("F")) {
this.shown = shown;
} else if (shown.equals("?")) {
this.shown = shown;
} else {
this.shown = "Error + shown";
}
*/
if (validShownTextSet.contains(shown)) {
this.shown = shown;
} else {
this.shown = "Error" + shown;
}
}
}
答案 0 :(得分:2)
这一行
private static final String[] VALID_SHOWN_TEXT = {"X", 0 < minecount && _minecount < 8, " ", "F", "?"};
有一些问题。这里的范围没有minecount
变量。变量_minecount
不是静态变量,因此通过使VALID_SHOWN_TEXT
静态变为静态范围,无法访问它。
看起来你已经猜到了,你不能将boolean
从表达式0 < minecount && _minecount < 8
存储到String
数组中。即使您可以使用boolean
表达式,您也必须将其转换为String
才能将其存储到String
数组中。
// or a working boolean expression here.
..., String.valueOf(0 < minecount && _minecount < 8), ...
HashSet<Object>
可以包含整数和字符串,但是在这里,您可以简单地将所需内容转换为字符串数组,该字符串数组应该能够转换为HashSet<String>
。< / p>