Question

我有一个包含以下列的表

defect_id, developer_name, status, summary, root_cause, 
Secondary_RC, description, Comments, environment_name

专栏root_cause包含Enviro，Requi，Dev，TSc，TD，Unkn作为其值和列environment_name具有QA1，QA2，QA3

我需要以下面的格式准备一份报告

    Enviro Requi  Dev TSc  TD Unkn  Total
QA1    9    1     14   17   2   3   46
QA2    8    1     14   0    5   1   29
QA3    1    1      7   0    0   1   10
Total 18    3     35   17   7   5   85

我已准备好报告

    Enviro Requi  Dev  TSc  TD Unkn 
QA1    9    1     14    17   2  3   
QA2    8    1     14    0    5  1   
QA3    1    1      7    0    0  1

我使用以下查询来获得上述结果

select *
from
(
  select environment_name as " ", value
  from test1 
  unpivot
  (
     value
    for col in (root_cause)
  ) unp
) src
pivot
(
  count(value)
  for value in ([Enviro] , [Requi] , [Dev] , [Tsc], [TD] , [Unkn])
) piv

任何人都可以帮助获取列和行的总数吗？

Answer 1

可能有各种方法。您可以计算枢轴后的所有总计，或者您可以先获得总计，然后转动所有结果。也有可能有一种中间立场：获得一种总数（例如行式），枢轴，然后得到另一种，尽管这可能是过度的。

上面提到的第一种方法，在枢轴之后得到所有总数，可以非常直接的方式完成，并且在下面的实现中唯一可能是新的东西可能是GROUP BY ROLLUP()：

SELECT
  [ ]      = ISNULL(environment_name, 'Total'),
  [Enviro] = SUM([Enviro]),
  [Requi]  = SUM([Requi]),
  [Dev]    = SUM([Dev]),
  [Tsc]    = SUM([Tsc]),
  [TD]     = SUM([TD]),
  [Unkn]   = SUM([Unkn]),
  Total    = SUM([Enviro] + [Requi] + [Dev] + [Tsc] + [TD] + [Unkn])
FROM (
  SELECT environment_name, root_cause
  FROM test1
) s
PIVOT (
  COUNT(root_cause)
  FOR root_cause IN ([Enviro], [Requi], [Dev], [Tsc], [TD], [Unkn])
) p
GROUP BY
  ROLLUP(environment_name)
;

基本上，GROUP BY ROLLUP()部分会为您生成Total 行。分组首先由environment_name完成，然后添加总计行。

要做相反的事情，即在转动之前得到总数，你可以像这样使用GROUP BY CUBE()：

SELECT
  [ ]      = environment_name,
  [Enviro] = ISNULL([Enviro], 0),
  [Requi]  = ISNULL([Requi] , 0),
  [Dev]    = ISNULL([Dev]   , 0),
  [Tsc]    = ISNULL([Tsc]   , 0),
  [TD]     = ISNULL([TD]    , 0),
  [Unkn]   = ISNULL([Unkn]  , 0),
  Total    = ISNULL(Total   , 0)
FROM (
  SELECT
    environment_name = ISNULL(environment_name, 'Total'),
    root_cause       = ISNULL(root_cause,       'Total'),
    cnt              = COUNT(*)
  FROM test1
  WHERE root_cause IS NOT NULL
  GROUP BY
    CUBE(environment_name, root_cause)
) s
PIVOT (
  SUM(cnt)
  FOR root_cause IN ([Enviro], [Requi], [Dev], [Tsc], [TD], [Unkn], Total)
) p
;

这两种方法都可以在SQL Fiddle中进行测试和播放：

注意。我已经省略了两个建议中的隐蔽步骤，因为对单个列进行拆分似乎显然是多余的。但是，如果有更多内容，调整其中一个查询应该很容易。

Answer 2

您可以使用root_cause找到environment_name和ROLLUP的总计。

RNO_COLTOTAL - 将Total放在最后一列的逻辑，因为列Tsc，Unkn在旋转时会与列Total重叠，因为它的排序按字母顺序。
RNO_ROWTOTAL - 将Total放在最后一行的逻辑，因为值以U，W，X，Y开头，Z可以重叠值Total，因为它按字母顺序排序。
SUM(VALUE) - 可以定义我们可以使用ROLLUP的聚合函数。

QUERY 1

SELECT CASE WHEN root_cause IS NULL THEN 1 ELSE 0 END RNO_COLTOTAL, 
CASE WHEN environment_name IS NULL THEN 1 ELSE 0 END RNO_ROWTOTAL,
ISNULL(environment_name,'Total')environment_name,
ISNULL(root_cause,'Total')root_cause,
SUM(VALUE) VALUE
INTO #NEWTABLE
FROM
(
    -- Find the count for environment_name,root_cause
    SELECT DISTINCT *,COUNT(*) OVER(PARTITION BY environment_name,root_cause)VALUE 
    FROM #TEMP
)TAB
GROUP BY root_cause,environment_name
WITH CUBE

使用CUBE时，我们将获得以下逻辑

enter image description here

我们声明了用于旋转的变量。

@cols - 用于旋转的列值。
@NulltoZeroCols - 将空值替换为零。

QUERY 2

DECLARE @cols NVARCHAR (MAX)

SELECT @cols = COALESCE (@cols + ',[' + root_cause + ']', 
               '[' + root_cause + ']')
               FROM    (SELECT DISTINCT RNO_COLTOTAL,root_cause FROM #NEWTABLE) PV 
               ORDER BY  RNO_COLTOTAL,root_cause 

DECLARE @NulltoZeroCols NVARCHAR (MAX)

SET @NullToZeroCols = SUBSTRING((SELECT ',ISNULL(['+root_cause+'],0) AS ['+root_cause+']' 
FROM(SELECT DISTINCT RNO_COLTOTAL,root_cause FROM #NEWTABLE GROUP BY RNO_COLTOTAL,root_cause)TAB  
ORDER BY RNO_COLTOTAL  FOR XML PATH('')),2,8000)

现在动态转动

DECLARE @query NVARCHAR(MAX)
SET @query = 'SELECT environment_name,'+ @NulltoZeroCols +' FROM 
             (
                 SELECT RNO_ROWTOTAL,environment_name,root_cause,VALUE
                 FROM #NEWTABLE
             ) x
             PIVOT 
             (
                 MIN(VALUE)
                 FOR [root_cause] IN (' + @cols + ')
            ) p
            ORDER BY RNO_ROWTOTAL,environment_name;' 

EXEC SP_EXECUTESQL @query

<强> RESULT

enter image description here

Answer 3

我认为您需要单独计算总计。使用这个简单的查询总计（抱歉，必须为您的“”列提供别名）：

select environment_name as en, 
count (*) AS Total
FROM test1 
WHERE value in ('Enviro', 'Requi', 'Dev', 'Tsc', 'TD', 'Unkn')
GROUP BY environment_name

您可以轻松地将两个查询一起加入以获取所需的报告：

SELECT * FROM
(select *
from
(
  select environment_name as en, value
  from test1 
  unpivot
  (
     value
    for col in (root_cause)
  ) unp
) src
pivot
(
  count(value)
  for value in ([Enviro] , [Requi] , [Dev] , [Tsc], [TD] , [Unkn])
) piv
) AS a 
INNER JOIN
( select environment_name as en, 
  count (*) AS Total
  FROM test1 
  WHERE value in ('Enviro', 'Requi', 'Dev', 'Tsc', 'TD', 'Unkn')
  GROUP BY environment_name
 ) AS b ON a.en = b.en
UNION ALL
SELECT * FROM
(select *
from
(
  select 'Total' as en, value
  from test1 
  unpivot
  (
     value
    for col in (root_cause)
  ) unp
) src
pivot
(
  count(value)
  for value in ([Enviro] , [Requi] , [Dev] , [Tsc], [TD] , [Unkn])
) piv
) AS a 
INNER JOIN
( select 'Total' as en, 
  count (*) AS Total
  FROM test1 
  WHERE value in ('Enviro', 'Requi', 'Dev', 'Tsc', 'TD', 'Unkn')
 ) AS b

我没有测试过，但相信它会起作用

在sql server 2008中使用包含列和行总计的数据透视表

3 个答案: