[免责声明:我是PHP的新手,我只是在学习,所以请不要浪费,当人们试图找到解决方案或信息时,它确实阻碍了学习过程,谢谢你,代码工作得很好填字游戏,它真的让我感到困惑的是如何用给定的信息获得对角线方向,或者我做错了什么而没看到?]
给出一个开关:
switch ($dir){
case "E":
//col from 0 to board width - word width
//row from 0 to board height
$newCol = rand(0, $boardData["width"] - 1 - strlen($theWord));
$newRow = rand(0, $boardData["height"]-1);
for ($i = 0; $i < strlen($theWord); $i++){
//new character same row, initial column + $i
$boardLetter = $board[$newRow][$newCol + $i];
$wordLetter = substr($theWord, $i, 1);
//check for legal values in current space on board
if (($boardLetter == $wordLetter) ||
($boardLetter == ".")){
$board[$newRow][$newCol + $i] = $wordLetter;
} else {
$itWorked = FALSE;
} // end if
} // end for loop
break;
和
case "N":
//col from 0 to board width
//row from word length to board height
$newCol = rand(0, $boardData["width"] -1);
$newRow = rand(strlen($theWord), $boardData["height"]-1);
for ($i = 0; $i < strlen($theWord); $i++){
//check for a legal move
$boardLetter = $board[$newRow - $i][$newCol];
$wordLetter = substr($theWord, $i, 1);
if (($boardLetter == $wordLetter) ||
($boardLetter == ".")){
$board[$newRow - $i][$newCol] = $wordLetter;
} else {
$itWorked = FALSE;
} // end if
} // end for loop
break;
我应该能够将两者结合起来(或将对角线文本输出到屏幕上)
但是,当我尝试这个时,它不起作用,我一直在尝试不同的组合 N和E得到NE或对角线NE方向没有运气,是什么给出了?
#Tried multiple different combination's of N & E, I am out of ideas
switch ($dir){
case "E":
$newCol = rand(0, $boardData["width"] - 1 - strlen($theWord));
$newRow = rand(strlen($theWord), $boardData["height"]-1);
for ($i = 0; $i < strlen($theWord); $i++){
#Combined but no luck, WTF:
$boardLetter = $board[$newRow][$newRow - $i];
$boardLetter = $board[$newCol][$newCol + $i];
$wordLetter = substr($theWord, $i, 1);
//check for legal values in current space on board
if (($boardLetter == $wordLetter) ||
($boardLetter == ".")){
$board[$newRow][$newRow - $i] = $wordLetter;
$board[$newCol][$newCol + $i] = $wordLetter;
} else {
$itWorked = FALSE;
} // end if
} // end for loop
break;
答案 0 :(得分:2)
运行break;
的代码后,switch
语句将突破case "E"
子句。您需要为组合设置新的显式案例,以使其以这种方式工作。