Question

我的程序尚未完成，但我需要帮助才能找到一种方法来运行我的方法6次。这是一个数学练习游戏，该方法输出问题并计算答案。理想情况下，id方法运行6次（总共6个数学问题），然后输出“LEVEL ONE COMPLETE”语句。但每当我运行它时，它会在每个问题的末尾输出“LEVEL ONE COMPLETE”。此外，每次用户正确回答问题时，金额（int amount = 0;）都不会增加（amount+=150;）。我是初学者，所以请帮助我们！

还有一件事......如果我想让游戏结束，如果用户得到3个错误的答案，我应该如何将它包含在我的代码中？

谢谢！

这是我在main方法中调用方法的地方..运行它6次：

  for (int loop = 0; loop <= 6; loop++) { findAdd() }

这是我调用的方法（包含数学问题）：

public static int findAdd ()
 {
   Object[] optionsA = {"Yes Please", "Nope! I'm good!"};
   int wrong = 0;
   int amount = 0;
   int increment = 150;
   int questionnum = 0;
   questionnum ++;
   int numOne = (int)(Math.random () * 30);
   int numTwo = (int)(Math.random () * 30);
   int answer = numOne + numTwo;

   String useranswerA = JOptionPane.showInputDialog(null,"Question #" + questionnum + " is for: $" + increment + "\n" + numOne + " + " + numTwo + " = ?", "Question", JOptionPane.INFORMATION_MESSAGE);
    int useranswer = Integer.parseInt(useranswerA);

        if (useranswer != answer)
        {
          wrong ++;
          JOptionPane.showMessageDialog(null,"You got the wrong answer! \n The correct answer is: " + answer + " \n Questions Wrong: " + wrong, "Wrong Answer", JOptionPane.INFORMATION_MESSAGE);
          int y = JOptionPane.showOptionDialog(null,"CASH OUT with a total of $" + amount + "?","Cash Out?", JOptionPane.YES_NO_OPTION,JOptionPane.QUESTION_MESSAGE,null,optionsA,optionsA[0]);
          if (y == JOptionPane.YES_OPTION) {
            JOptionPane.showMessageDialog(null,"Thanks for Playing!", "Thank You!", JOptionPane.INFORMATION_MESSAGE);
            System.exit(0);
          }
          if (y == JOptionPane.NO_OPTION) {}
        }
        else if (useranswer == answer)
        {
          amount+=150;
          JOptionPane.showMessageDialog(null,"Correct!", "Right Answer", JOptionPane.INFORMATION_MESSAGE);
          int y = JOptionPane.showOptionDialog(null,"CASH OUT with a total of $" + amount + "?","Cash Out?", JOptionPane.YES_NO_OPTION,JOptionPane.QUESTION_MESSAGE,null,optionsA,optionsA[0]);
          if (y == JOptionPane.YES_OPTION) {
            JOptionPane.showMessageDialog(null,"Thanks for Playing!", "Thank You!", JOptionPane.INFORMATION_MESSAGE);
            System.exit(0);
          }
          if (y == JOptionPane.NO_OPTION) {}
        }


     JOptionPane.showMessageDialog(null,"LEVEL ONE COMPLETE!", "LEVEL 1", JOptionPane.INFORMATION_MESSAGE);
     JOptionPane.showMessageDialog(null,"Cash on Hand: $ " + amount, "Cash", JOptionPane.INFORMATION_MESSAGE);
      return useranswer;
   }

Answer 1

首先，这会调用函数7次，而不是6次：

for (int loop = 0; loop <= 6; loop++) { findAdd() }

但更重要的是，这个功能正是你所描述的。它提出了一个问题，得到了一个回复，然后每次打电话都打印出“LEVEL ONE COMPLETE”，因为这就是你写它的方式。此外，变量amount是函数的本地变量，因此每次调用函数时，它都会更新，然后当函数返回时值超出范围，抛弃您刚刚计算的内容。

“amount”变量和“LEVEL COMPLETE”消息都需要移出函数。你如何做到这一点是一个选择问题。您可能也希望变量amount也是静态的（取决于您未向我们展示的其余代码）。

Answer 2

从findAdd

中删除最后两行

 JOptionPane.showMessageDialog(null,"LEVEL ONE COMPLETE!", "LEVEL 1", JOptionPane.INFORMATION_MESSAGE);
 JOptionPane.showMessageDialog(null,"Cash on Hand: $ " + amount, "Cash", JOptionPane.INFORMATION_MESSAGE);

并在您调用findAdd六次的地方调用它们：

int amount; //amount goes out of the `findAdd()`
int useranswer;
for (int i=0; i<6; ++i) {
    useranswer = findAdd();
    if (useranswer == JOptionPane.YES_OPTION) { //quit?
        return; //exit?   
    }
}
JOptionPane.showMessageDialog(null,"LEVEL ONE COMPLETE!", "LEVEL 1", JOptionPane.INFORMATION_MESSAGE);
JOptionPane.showMessageDialog(null,"Cash on Hand: $ " + amount, "Cash", JOptionPane.INFORMATION_MESSAGE);

Answer 3

您的金额需要在findAdd()方法之外编写。

int amount = 0;

以下内容也需要移动到for循环后显示，而不是findAdd()方法。

 JOptionPane.showMessageDialog(null,"LEVEL ONE COMPLETE!", "LEVEL 1", JOptionPane.INFORMATION_MESSAGE);
 JOptionPane.showMessageDialog(null,"Cash on Hand: $ " + amount, "Cash", JOptionPane.INFORMATION_MESSAGE);

示例：

int amount = 0;

for (int i = 0; i < 6; i++)
{
    findAdd();
}

JOptionPane.showMessageDialog(null,"LEVEL ONE COMPLETE!", "LEVEL 1", JOptionPane.INFORMATION_MESSAGE);
JOptionPane.showMessageDialog(null,"Cash on Hand: $ " + amount, "Cash", JOptionPane.INFORMATION_MESSAGE);

重复方法

3 个答案: