我有这样的数据源
var source = [
{
group: "g-one",
item: "one"
},
{
group: "g-one",
item: "two"
},
{
group: "g-one",
item: "three"
},
{
group: "g-two",
item: "aaa"
},
{
group: "g-two",
item: "bbb"
}
];
从此我需要创建一个像这样的结构
<div id='g-one'>
<div>one</div>
<div>two</div>
<div>three</div>
</div>
<div id='g-two'>
<div>aaa</div>
<div>bbb</div>
</div>
请帮我解决这个问题
答案 0 :(得分:2)
jQuery Way
首先将这些小组排除在外:
var groups = $.unique($.map(source, function (n) {
return n.group;
}));
迭代groups
数组并获得输出:
$.each(groups, function (i, data) {
$("<div/>", {
"id": data.group,
"html": function () {
var elmts = $.grep(source, function (a) {
return a.group === data;
});
return $.map(elmts, function (n) {
return "<div>" + n.item + "</div>";
}).join(" ");
}
}).appendTo("body");
});
演示:http://jsfiddle.net/hungerpain/nZTvp/6/
仅使用JavaScript
使用for
循环迭代并创建元素。要获取字符串,请使用字符串连接。
var group = source[0].group;
var html = "<div id='" + group + "'>";
var elemts = [];
for (var i = 0; i <= source.length; i++) {
if (i !== source.length) {
if (group === source[i].group) {
html += "<div>" + source[i].item + " </div>";
} else {
html += "</div>";
elemts.push(html);
group = source[i].group;
html = "<div id='" + group + "'><div>" + source[i].item + " </div>";
}
} else {
html += "</div>";
elemts.push(html);
}
}
答案 1 :(得分:1)
var source = [ { group: "g-one", item: "one" }, { group: "g-one", item: "two" }, { group: "g-one", item: "three" }, { group: "g-two", item: "aaa" }, { group: "g-two", item: "bbb" } ];
var a=new Array();
for(var i=0;i<source.length;i++)
{
a[i]=source[i].group;
}
b = {};
for (var i = 0; i < a.length; i++)
{
b[a[i]] = a[i];
}
c = [];
for (var key in b)
{
c.push(key);
}
var message = "";
for(var i=0;i<c.length;i++)
{
message+="<div id = '"+c[i]+"'>"
for(var j=0;j<source.length;j++)
{
if(c[i] == source[j].group)
{
message+="<div>"+source[j].item+"</div>";
}
}
message+="</div>";
}
alert(message);