在android中获取位置的AsyncTask出错“无法在未调用looper.prepare()的线程内创建处理程序”

时间:2013-06-15 07:29:21

标签: android gps

所有

我仔细阅读了本网站上的许多相关问答,但没有任何帮助。这是我的代码,它可以正常使用GPS,但一旦关闭GPS就出错了。

/**
 * 
 * @author Jimmy Chiang
 * 
 */
public class GetLocationTask extends AsyncTask<Context, Void, Location> {

    private OnLocationListener[] mGpsListeners;
    private Location location;

    private LocationListener locationListener = new LocationListener() {

        @Override
        public void onLocationChanged(Location lo) {
            location = lo;
        }

        @Override
        public void onStatusChanged(String provider, int status, Bundle extras) {
            // TODO Auto-generated method stub

        }

        @Override
        public void onProviderEnabled(String provider) {
            // TODO Auto-generated method stub

        }

        @Override
        public void onProviderDisabled(String provider) {
            // TODO Auto-generated method stub

        }
    };

    public interface OnLocationListener {
        public void onLocationGot(Location location);
    }

    public GetLocationTask setOnLocationListener(
            OnLocationListener... listeners) {
        mGpsListeners = listeners;
        return this;
    }

    @Override
    protected Location doInBackground(Context... params) {


        LocationManager locationManager = (LocationManager) params[0]
                .getSystemService(Context.LOCATION_SERVICE);

        String provider = LocationManager.NETWORK_PROVIDER;
        if (locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER)) {

            provider = LocationManager.GPS_PROVIDER;

        }
        location = locationManager.getLastKnownLocation(provider);

        while (location == null) {

            locationManager.requestLocationUpdates(provider, 1000, 1,locationListener);
        }
        return location;
    }

    @Override
    protected void onPostExecute(Location location) {

        for (OnLocationListener listener : mGpsListeners) {
            listener.onLocationGot(location);
        }
    }
}

例外情况显示:

  

无法在未调用的线程内创建处理程序   looper.prepare()

有些帖子显示问题应该是在UI Thread中调用someting,但我找不到任何这个。非常感谢,如果你知道发生了什么〜

1 个答案:

答案 0 :(得分:7)

变化

locationManager.requestLocationUpdates(provider, 1000, 1,locationListener);

locationManager.requestLocationUpdates(provider, 1000, 1,locationListener, Looper.getMainLooper());

作为文档中的标记

Looper.getMainLooper()
  

返回应用程序的主循环程序,它位于主线程中   的   应用

requestLocationUpdate的looper参数是一个Looper对象,其消息队列将用于实现回调机制,或null以在调用线程上进行回调。

如果您希望AsyncTask成为将接收您必须使用的消息的

  Looper.myLooper().prepare();
  locationManager.requestLocationUpdates(provider, 1000, 1,locationListener, Looper.myLooper());