Question

我正在尝试将空页脚（LinearLayout）添加到我的ListView并在以下情况下用我自己的视图填充此页脚：

private View footerButton;
private LinearLayout footer;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.rlist);

    footer=new LinearLayout(this);
    footer.setLayoutParams(new ListView.LayoutParams(ListView.LayoutParams.MATCH_PARENT, ListView.LayoutParams.WRAP_CONTENT));

    footerButton=((LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE)).inflate(R.layout.footer_button, null, false);

    ListView list=(ListView) findViewById(R.id.list);
    list.addFooterView(footerButton,null,false);

    final UsersListAdapter adapter = new UsersListAdapter(this);
    list.setAdapter(adapter);

    //...

    new Thread() {
        @Override
        public void run() {

            //Loading...

            runOnUiThread(new Runnable() {
                public void run() {
                    adapter.notifyDataSetChanged();

                    footer.removeAllViews();
                    footer.addView(footerButton);
                }
            });
        }
    }.start();
}

但我在行“footer.addView（footerButton）;”中得到例外：“

java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

为什么呢？如您所知，我在添加任何视图之前调用removeAllViews()。如何解决？

Answer 1

这是因为您在ListView对象中添加了 footerButton

查看此行..

list.addFooterView(footerButton,null,false);

所以，现在footerButton有一个父类，即列表..所以你在添加到LinearLayout页脚时出错

尝试removeView()列表...

LinearLayout.removeAllViews（）不起作用（IllegalStateException）

1 个答案: