图形仅使用KeyListener向右移动1个像素

时间:2013-06-10 23:17:08

标签: java swing graphics keylistener paintcomponent

我是Java编程的新手,我正在开发我的第一个2D游戏。我按照Oracle关键监听器的一个教程来了解如何使用WASD键移动我的播放器。该示例已经有一个鼠标监听器。我决定删除鼠标监听器并添加KeyListener。我为D添加了一个KeyListener,它将我的图形向右移动。但是,我的图形只向右移动1个坐标而不是更新正方形的新位置,并且每当按下D键时将其移动到连续循环中。我正在使用绘画组件来绘制我的图像。

这是我的班级:

import javax.swing.SwingUtilities;
import java.awt.event.KeyListener;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.BorderFactory;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import java.awt.event.KeyEvent;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;
import java.awt.event.MouseAdapter;
import java.awt.event.MouseMotionListener;
import java.awt.event.MouseMotionAdapter;

public class PaintComponent {

    public static void main(String[] args) {
        SwingUtilities.invokeLater(new Runnable() {
            public void run() {
                createAndShowGUI();
            }
        });
    }

    private static void createAndShowGUI() {
        System.out.println("Created GUI on EDT? "
                + SwingUtilities.isEventDispatchThread());
        JFrame f = new JFrame("Swing Paint Demo");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        f.add(new MyPanel());
        f.pack();
        f.setVisible(true);
    }

}

class MyPanel extends JPanel {

    private int squareX = 50;
    private int squareY = 50;
    private int squareW = 20;
    private int squareH = 20;
    public int posX = squareX;
    public int posY = squareY;

    public MyPanel() {
        setFocusable(true);
        requestFocusInWindow();

        setBorder(BorderFactory.createLineBorder(Color.black));

        addKeyListener(new KeyListener() {
            @Override
            public void keyTyped(KeyEvent e) {
                // TODO Auto-generated method stub

            }

            @Override
            public void keyPressed(KeyEvent e) {
                // TODO Auto-generated method stub
                int keyCode = e.getKeyCode();

                if (keyCode == KeyEvent.VK_D) {

                    moveSquareRight(posX);

                } else {
                    e.consume();
                }
            }

            @Override
            public void keyReleased(KeyEvent e) {
                // TODO Auto-generated method stub
                int keyCode = e.getKeyCode();
                e.consume();

            }
        });
        /*
         * addMouseListener(new MouseAdapter() { public void
         * mousePressed(MouseEvent e) { moveSquare(e.getX(),e.getY()); } });
         * 
         * addMouseMotionListener(new MouseAdapter() { public void
         * mouseDragged(MouseEvent e) { moveSquare(e.getX(),e.getY()); } });
         */

    }

    private void moveSquareRight(int x) {
        int OFFSET = 1;

            if (squareX == x) {

                repaint(squareX, squareY, squareW + OFFSET, squareH + OFFSET);
                squareX = x + 1;
                repaint(squareX, squareY, squareW + OFFSET, squareH + OFFSET);
            }

        }



    public Dimension getPreferredSize() {
        return new Dimension(250, 200);
    }

    protected void paintComponent(Graphics g) {
        super.paintComponent(g);
        g.drawString("This is my custom Panel!", 10, 20);
        g.setColor(Color.RED);
        g.fillRect(squareX, squareY, squareW, squareH);
        g.setColor(Color.BLACK);
        g.drawRect(squareX, squareY, squareW, squareH);
    }

}

1 个答案:

答案 0 :(得分:4)

  

我正在考虑将posX转换为数组并为其添加for循环,

不,你不需要循环。

moveSquareRight(posX);

没有必要将posX作为参数传递,因为它是每个方法都可以访问它的类变量。

  

虽然posX没有改变,因此它保持在同一位置。

所以更新posX。

if (squareX == x) {
    repaint(squareX, squareY, squareW + OFFSET, squareH + OFFSET);
    squareX = x + 1;
    repaint(squareX, squareY, squareW + OFFSET, squareH + OFFSET);
}

您正在使上述代码过于复杂。尝试类似:

posX++;
repaint();

您不希望指定要重绘的矩形(),因为在将矩形绘制到新位置之前,不会清除旧绘画。

您还应该查看Motion Using the Keyboard以了解移动组件的方法。