如何将正数和负数分成自己的列？

Question

我有一个包含以下列和数据的表：

activity_dt | activity_amt
 2009-01-01 |   -500
 2009-01-01 |    750

我是否可以编写一个查看activity_amt符号的查询，如果是正数则将其放入信用列，如果是负数，则将其存入借方列？ （我正在使用Sybase）

activity_dt | debits | credits
 2009-01-01 |  -500  |   750

Answer 1

select activity_dt, 
    sum(case when activity_amt < 0 then activity_amt else 0 end) as debits, 
    sum(case when activity_amt > 0 then activity_amt else 0 end) as credits
from the_table
group by activity_dt
order by activity_dt

Answer 2

我不确定Sybase中的确切语法，但您应该能够对日期进行分组并总结正值和负值：

select
  activity_dt,
  sum(case when activity_amt < 0 then activity_amt else 0 end) as debits,
  sum(case when activity_amt >= 0 then activity_amt else 0 end) as credits
from
  theTable
group by
  activity_dt

Answer 3

select (select JV_GroupsHead.GroupTitle
         from JV_GroupsHead
         whereJV_GroupsHead.Id=jv.GroupId) as 'GroupName'
        ,jv.Revenue
        ,jv.AccountNo
        ,jv.AccountNoTitle
        ,(case when jv.Revenue  < 0 then jv.Revenue  else 0 end) as 'debits'
        ,(case when jv.Revenue> 0 then jv.Revenue  else 0 end) as 'credits'
from JVFunction1('2010-07-08','2010-08-08') as jv

Answer 4

我使用DECODE函数找到了这个问题的新答案。 我希望这对每个人都有用。

select activity_dt, 
sum((DECODE(activity_amt /-ABS(activity_amt), 1, activity_amt, 0))) as credits,
sum((DECODE(activity_amt /-ABS(activity_amt), -1, activity_amt, 0))) as debits
from the_table
group by activity_dt
order by activity_dt;