Question

我有三个用json编码的PHP数组...因为数组工作正常而省略了额外的PHP代码....此外，为了简洁起见，省略了调用谷歌图表的HTML标记......

<?php
$encoded_line_volume = json_encode($LineVol) . "\n";
$encoded_loan_volume = json_encode($LoanVol) . "\n";
$encoded_cluster_name = json_encode($ClusterLine) . "\n";
?>

我想在Javascript中访问这三个数组，以动态更新我的Google图表。

<script type="text/javascript">

google.load("visualization", "1", {packages:["columnchart"]});
google.setOnLoadCallback(drawChart);

var linevol = new Array;  // This would be the first array passed from PHP
var loanvol = new Array;  // This would be the second array passed from PHP
var clusters = new Array; // This would be the third array passed from PHP

function drawChart() {
    var data = new google.visualization.DataTable();

    data.addColumn('string', 'Cluster');
    data.addColumn('number', 'Loans');
    data.addColumn('number', 'Lines');

/* create for loops to add as many columns as necessary */

var len = jsonarray.length;

    data.addRows(len);

for(i=0; i<len; i++) {

data.setValue(i, 0, ' '+clusters[i]+'');     /* x-axis */
data.setValue(i, 1, linevol[i]);   /* Y-axis category #1*/
data.setValue(i, 2, loanvol[i]);   /* Y-axis category #2*/
}
/*********************************end of loops***************************************/
  var chart = new google.visualization.ColumnChart(document.getElementById('chart_div'));
  chart.draw(data, {width: 400, height: 240, is3D: true, title: 'Prospect Population', legend: 'right'});
}
</script>

Answer 1

您可能希望它们成为Javascript变量。当您的PHP执行时，它会创建您的Web浏览器然后解释的代码。所以你想用php定义javascript字符串。例如：

<script type="text/javascript">
    var encoded_line_volume = <?php echo json_encode($LineVol) ?>;
    var encoded_loan_volume = <?php echo json_encode($LoanVol) ?>;
    var encoded_cluster_name = <?php echo json_encode($ClusterLine) ?>;
</script>

然后这些变量可以被后续的javascript访问。

Answer 2

这是如何从PHP动态生成数据，正确生成JSON格式的输出并从JavaScript读取它（需要JQuery）并将其加载到Google Visulization（Charts）API。

PHP（服务器）方：

function returnData() {
    $data = Array ();
    $data [] = Array ("Name", "Value");
    $data [] = Array ("Apple", 5);
    $data [] = Array ("Banana", 3);

    header('content-type: application/json');
    echo json_encode($data);
 }

Javascript（客户端）方：

var jsonData = null;

var jsonDataResult = $.ajax({
    url: dataURL,
    dataType: "json",
    async: false,
    success: (
        function(data) {
            jsonData = data;
        })
});

var data = new google.visualization.arrayToDataTable(jsonData);

Answer 3

这是我做过的最好的例子之一，它可以帮助你：它经过测试和运行良好：创建两个页面，一个名为index.php，另一个名为get_json.php：这不完全是您发布的代码，但完全相同的想法，它回答了问题。

the codes for index.php 

    <html>
    <head>
        <title>King Musa Graph</title>
        <!-- Load jQuery -->
        <script language="javascript" type="text/javascript" 
            src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js">
        </script>
        <!-- Load Google JSAPI -->
        <script type="text/javascript" src="https://www.google.com/jsapi"></script>
        <script type="text/javascript">
            google.load("visualization", "1", { packages: ["corechart"] });
            google.setOnLoadCallback(drawChart);

            function drawChart() {
                var jsonData = $.ajax({
                    url: "get_json.php",
                    dataType: "json",
                    async: false
                }).responseText;

                var obj = jQuery.parseJSON(jsonData);
                var data = google.visualization.arrayToDataTable(obj);

                var options = {
                    title: 'King Musa'
                };

                var chart = new google.visualization.LineChart(
                            document.getElementById('chart_div'));
                chart.draw(data, options);
            }

        </script>
    </head>
    <body>
        <div id="chart_div" style="width: 900px; height: 500px;">
        </div>
    </body>
    </html> 

codes for get_json.php
<?php

    $data = Array ();
    $data [] = Array ("Name", "Value");
    $data [] = Array ("PHP", 78);

    $data [] = Array ("JAVA", 1000);
  $data [] = Array ("HTML", 129);


    $table = json_encode($data);
   // header('content-type: application/json'); 

    echo $table ; // this line is important it should be not disabled 

?>

通过JSON将PHP数组传递到Javascript以更新Google Chart

3 个答案: