Question

这段代码获取所有表单变量，并通过AJAX将它们发送到PHP脚本。但我希望通过JSON编码数组返回到javascript的PHP脚本的计算结果为“post”形式：{“uname”：“someNamefromForm”，“email”：“someEmail”，“ FNAME “：” namefromtheform”， “L-NAME”： “lastnamefromform” 我现在得到的输出是“uname = e＆amp; email = e＆amp; fname = e＆amp; lname = euname”..这是我想在页面底部显示的JSON数组，用于调试目的。有人可以告诉我如何格式化它

这是我的HTML表单

  <div id="wrapper">
      <h2> Validation with AJAX,JQuery,JSON and PHP</h2>
          <div class="form-container">    
              <span id="ajax-message"></span>

              <form id="ajax-form" onsubmit="return false;">
                  <p class="legend">All fields marked with an asterisk are required.</p>

                  <fieldset>
                      <legend>User Details</legend>
                      <div>
                        <label for="uname">Username <em>*</em></label> 
                        <input id="uname" type="text" name="uname" value=""  />
                      </div>
                      <div>
                        <label for="email">Email Address <em>*</em></label> 
                        <input id="email" type="text" name="email" value="" />
                      </div>
                      <div>
                        <label for="fname" class="error">First Name <em>*</em></label> 
                        <input id="fname" type="text" name="fname" value="" size="50" class="error"/>
                        <p class='note'>All error message go here </p> 
                      </div>
                      <div>
                        <label for="lname">Last Name <em>*</em></label> 
                        <input id="lname" type="text" name="lname" value="" size="50" />
                      </div>
                  </fieldset>

                  <div class="buttonrow">
                      <input type="submit" value="Submit This Form via AJAX" class="button" />  
                      <input type="button" value="Start Again" class="button" />
                      <a >Refresh this Page</a>
                  </div>
              </form>
          </div> 
      <h3>JSON Array</h3>
      <pre id='debug'></pre>
  </div>

这是我的javascript

$("#ajax-form").submit(function(){
          var variableToSend = $(this).serialize();
          $.post(
            'ajaxformval_post.php', 
            {variable: variableToSend}, 
            function(data){$("#debug").html(data)},
            "json"
          );
      })

这是php

<?php
    $variable = $_POST['variable'];

    echo json_encode($variable);

    /*$json = array(
        'booleanFlag' => TRUE,
        'someText' => "AJAX should be renamed AJAJ",
        'anArrayOfData' => array('name' => 'Mickey', 'ears' => 'very Big') 
    );*/

 ?>

Answer 1

您可以直接发送序列化变量：

$("#ajax-form").submit(function(){
      var variableToSend = $(this).serialize();
      $.post(
        'ajaxformval_post.php', 
         variableToSend, 
        function(data){$("#debug").html(data)},
        "json"
      );
  });

然后在服务器端输出json_encoded帖子：

<?php
    $variable = $_POST;

    echo json_encode($variable);
 ?>

Answer 2

您是否尝试从$ .post-method更改＆＃34; json＆＃34; -parameter？

根据文件https://api.jquery.com/jQuery.post/

dataType
Type: String
The type of data expected from the server. Default: Intelligent Guess (xml, json, script, text, html).

所以我想如果你给他＆＃34; json＆＃34;他会自动解码返回的数据。

通过JQuery $ .post将JavaScript数组传递给PHP

2 个答案: