Question

如何让我的搜索表单仅列出hidden = '0'; +其他选项的结果？

$stmt = $dbh->prepare("
SELECT *
FROM        users u
LEFT JOIN   menues m
ON          u.user_id = m.restaurant_id
WHERE       (restaurant LIKE CONCAT('%', :term, '%'))
OR          city LIKE CONCAT('%', :term, '%')
");
$stmt->bindParam(":term", $term);
$stmt->execute();

提前致谢：）

Answer 1

好吧，我希望我明白你的需要：

$stmt = $dbh->prepare("
SELECT *
FROM        users u
LEFT JOIN   menues m
ON          u.user_id = m.restaurant_id
WHERE       (((restaurant LIKE CONCAT('%', :term, '%'))
OR          city LIKE CONCAT('%', :term, '%'))
AND         hidden = 0)
");
$stmt->bindParam(":term", $term);
$stmt->execute();

Answer 2

你能不能只添加

AND hidden = '0'

到WHERE子句的末尾，以便查询结束

.
.
.
WHERE (restaurant LIKE ...
OR city LIKE ...)
AND hidden='0'

顺便说一下，hidden真的是基于字符的列吗？如果没有，您应该添加hidden=0（不带单引号）

查询：隐藏='0'

2 个答案: