Question

我有以下表格 -

Search Result
----------------
SearchResultID PK
ProductID FK
SearchQuery
WebsiteName
URL
IsFound
CreatedOn
BatchID
Name

SearchResultItem
-----------------
SearchResultItemID PK
SearchResultID FK
Name
Value

这些表具有一对多的关系，因此一个搜索结果可以包含许多搜索结果项。

我可以对这些表进行INNER JOIN，但显然每个搜索结果项都有一行。理想情况下，我希望每个搜索结果占一行，例如......

SearchResultID | ProductID | SearchQuery | WebsiteName | URL | IsFound | 
CreatedOn | BatchID | Name | SearchResultItemID | Name 1 | Value 1 | Name 2 | 
Value 2 | Name 3 | Value 3 |

这可能吗？如果是这样，有人可以指出我正确的方向，我将如何做到这一点 - 我认为这将是这样的，只有在ms-sql - one to many sql select into single row - mysql

Answer 1

您可以使用ROW_NUMBER()功能为每个搜索结果项目在每个搜索结果中排名：

SELECT  SearchResultItemID,
        SearchResultID,
        Name,
        Value,
        RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
FROM    SearchResultItem;

如果您有已知数量的项目，那么您可以使用聚合函数来获取每个名称/值对：

WITH RankedItem AS
(   SELECT  SearchResultItemID,
            SearchResultID,
            Name,
            Value,
            RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
    FROM    SearchResultItem
)
SELECT  SearchResultID,
        Name1 = MIN(CASE WHEN RowNumber = 1 THEN Name END),
        Value1 = MIN(CASE WHEN RowNumber = 1 then Value END),
        Name2 = MIN(CASE WHEN RowNumber = 2 THEN Name END),
        Value2 = MIN(CASE WHEN RowNumber = 2 then Value END),
        Name3 = MIN(CASE WHEN RowNumber = 3 THEN Name END),
        Value3 = MIN(CASE WHEN RowNumber = 3 then Value END),
        Name4 = MIN(CASE WHEN RowNumber = 4 THEN Name END),
        Value5 = MIN(CASE WHEN RowNumber = 4 then Value END)
FROM    RankedItem
GROUP BY SearchResultID;

然后，您可以将其重新连接到搜索结果表，提供完整查询：

WITH RankedItem AS
(   SELECT  SearchResultItemID,
            SearchResultID,
            Name,
            Value,
            RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
    FROM    SearchResultItem
), Items AS
(   SELECT  SearchResultID,
            Name1 = MIN(CASE WHEN RowNumber = 1 THEN Name END),
            Value1 = MIN(CASE WHEN RowNumber = 1 then Value END),
            Name2 = MIN(CASE WHEN RowNumber = 2 THEN Name END),
            Value2 = MIN(CASE WHEN RowNumber = 2 then Value END),
            Name3 = MIN(CASE WHEN RowNumber = 3 THEN Name END),
            Value3 = MIN(CASE WHEN RowNumber = 3 then Value END),
            Name4 = MIN(CASE WHEN RowNumber = 4 THEN Name END),
            Value4 = MIN(CASE WHEN RowNumber = 4 then Value END)
    FROM    RankedItem
    GROUP BY SearchResultID
)

SELECT  SearchResult.SearchResultID,
        SearchResult.ProductID,
        SearchResult.SearchQuery,
        SearchResult.WebsiteName,
        SearchResult.URL,
        SearchResult.IsFound,
        SearchResult.CreatedOn,
        SearchResult.BatchID,
        SearchResult.Name,
        Items.Name1,
        Items.Value1,
        Items.Name2,
        Items.Value2,
        Items.Name3,
        Items.Value3,
        Items.Name4,
        Items.Value4
FROM    SearchResult
        INNER JOIN Items
            ON SearchResult.SearchResultID = Items.SearchResultID;

<强> Example on SQL Fiddle

如果要返回可变数量的值，则需要使用动态SQL：

DECLARE @SQL NVARCHAR(MAX) = '';

SELECT  @SQL = @SQL + ',[Name' + rn + '], [Value' + rn + '] '
FROM    (   SELECT  DISTINCT
                    rn = CAST(ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID) AS VARCHAR)
            FROM    SearchResultItem
        ) p;

SET @SQL = 'WITH RankedItem AS
            (   SELECT  SearchResultItemID,
                        SearchResultID,
                        Name,
                        Value,
                        RowNumber = ROW_NUMBER() OVER(PARTITION BY SearchResultID ORDER BY SearchresultItemID)
                FROM    SearchResultItem
            ), UnPivoted AS
            (   SELECT  upvt.SearchResultID,
                        Name = upvt.n + CAST(RowNumber AS VARCHAR),
                        upvt.v
                FROM    RankedItem
                        UNPIVOT
                        (   n
                            FOR v IN ([Name], [Value])
                        ) upvt
            ), Pivoted AS
            (   SELECT  *
                FROM    UnPivoted
                        PIVOT
                        (   MAX(V)
                            FOR Name IN (' + STUFF(@SQL, 1, 1, '') + ')
                        ) pvt
            )
            SELECT  SearchResult.SearchResultID,
                    SearchResult.ProductID,
                    SearchResult.SearchQuery,
                    SearchResult.WebsiteName,
                    SearchResult.URL,
                    SearchResult.IsFound,
                    SearchResult.CreatedOn,
                    SearchResult.BatchID,
                    SearchResult.Name' + @SQL + '                       
            FROM    SearchResult
                    INNER JOIN Pivoted
                        ON SearchResult.SearchResultID = Pivoted.SearchResultID;';

EXECUTE SP_EXECUTESQL @SQL;

<强> Example on SQL Fiddle

N.B。我故意在动态sql中使用不同的方式来表示有多种方法来实现组合行的结果。

MS SQL - 一对多关系 - 需要返回单行

1 个答案: