我有以下表格
Users
Id
FirstName
LastName
样本数据
1,'Peter','Smith'
2,'John','Como'
Phones
Id
UserId
PhoneTypeId
Phone
ContactName
示例数据
1,1,4,'555-555-5551','Peter'
2,1,4,'555-555-5552','Paul'
3,1,4,'555-555-5553','Nancy'
4,1,4,'555-555-5554','Hellen'
PhoneTypes
Id
Type
包含样本数据
1 Home
2 Work
3 Cell
4 Emergency
我必须创建以下结果
UserId, UserFirstName, UserLastName, FirstEmergencyContactName, FirstEmergencyContactPhone, SecondEmergencyContactName, SecondEmergencyContactPhone, ThirdEmergencyContactName, ThirdEmergencyContactPhone, FourthEmergencyContactName, FourthEmergencyContactPhone, FifthEmergencyContactName, FifthEmergencyContactPhone
如何为每个拥有紧急联系人的用户创建一行?有些用户可能有一个紧急联系人,有些用户可能有很多,但我只需要其中的五个。
答案 0 :(得分:1)
这称为表旋转。由于您希望的结果不超过5个,因此您可以conditional aggregation
使用row_number
:
select id, firstname, lastname,
max(case when rn = 1 then contactname end) emergency_contact1,
max(case when rn = 1 then phone end) emergency_phone1,
max(case when rn = 2 then contactname end) emergency_contact2,
max(case when rn = 2 then phone end) emergency_phone2,
...
from (
select u.id, u.firstname, u.lastname, p.phone, p.contactname,
row_number() over (partition by u.id order by p.phonetypeid) rn
from users u
join phones p on u.id = p.userid
) t
group by id, firstname, lastname
答案 1 :(得分:1)
此外,您可以使用透视,无需动态SQL和硬编码,因为您只需要5个联系人/电话。示例如下:
Row
输出:
;WITH cte AS (
SELECT p.UserId,
FirstName,
LastName,
CAST(ContactName as nvarchar(100)) as ContactName,
CAST(Phone as nvarchar(100)) as ContactPhone,
CAST(ROW_NUMBER() OVER (PARTITION BY p.UserId ORDER BY pt.Id) as nvarchar(100)) as RN
FROM Users u
INNER JOIN Phones p
ON p.UserId = u.Id
INNER JOIN PhoneTypes pt
ON pt.Id = p.PhoneTypeId
WHERE pt.Id = 4
)
SELECT *
FROM (
SELECT UserId,
FirstName,
LastName,
[Columns]+RN as [Columns],
[Values]
FROM cte
UNPIVOT (
[Values] FOR [Columns] IN (ContactName, ContactPhone)
) as unp
) as t
PIVOT (
MAX([Values]) FOR [Columns] IN (ContactName1,ContactPhone1,ContactName2,ContactPhone2,ContactName3,ContactPhone3,
ContactName4,ContactPhone4,ContactName5,ContactPhone5)
) as pvt
我添加了更多联系人。