检索地址簿的数据并以字符串格式显示

Question

您好我正在开发一个应用程序，因为我有一个要求，当我点击按钮时我有一个按钮操作方法我应该检索整个地址簿联系人并以字符串的形式显示我该怎么做才能有人打电话给我用代码。我几天都无法做到这一点。

我不希望使用 ABPeoplePickerNavigationController 进行导航并访问它 ，我只需要点击按钮访问所有联系人并以字符串的形式显示。

Answer 1

尝试此功能适用于 iOS 6以及iOS 5.0或更早版本：

首先在链接二进制文件库

中添加以下框架

• 的 AddressBookUI.framework
• 的 AddressBook.framework

他们导入

#import <AddressBook/ABAddressBook.h>
#import <AddressBookUI/AddressBookUI.h>

然后使用以下代码

ABAddressBookRef addressBook = ABAddressBookCreate();

__block BOOL accessGranted = NO;

if (ABAddressBookRequestAccessWithCompletion != NULL) { // We are on iOS 6
    dispatch_semaphore_t semaphore = dispatch_semaphore_create(0);

    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
        accessGranted = granted;
        dispatch_semaphore_signal(semaphore);
    });

    dispatch_semaphore_wait(semaphore, DISPATCH_TIME_FOREVER);
    dispatch_release(semaphore);
}

else { // We are on iOS 5 or Older
    accessGranted = YES;
    [self getContactsWithAddressBook:addressBook];
}

if (accessGranted) {
    [self getContactsWithAddressBook:addressBook];
}

// Get the contacts.
- (void)getContactsWithAddressBook:(ABAddressBookRef )addressBook {
    NSArray *arrayOfPeople = (__bridge_transfer NSArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);

    NSUInteger index = 0;
    NSMutableArray *firstNames = [[NSMutableArray alloc] init];

    for(index = 0; index <= ([arrayOfPeople count] - 1); index++){
        ABRecordRef currentPerson = (__bridge ABRecordRef)[arrayOfPeople objectAtIndex:index];
        NSString *currentFirstName = (__bridge_transfer NSString *)ABRecordCopyValue(currentPerson, kABPersonFirstNameProperty);

        // If first name is empty then don't add to the array
        if (![currentFirstName length] == 0) {
            [firstNames addObject: currentFirstName];
        }

    }
    //OPTIONAL: Use the following line to sort the first names alphabetically
    NSArray *sortedFirstNames = [firstNames sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];
    NSLog(@"Total Count = %d \n Sorted By Name = %@", [sortedFirstNames count], sortedFirstNames);
}

我对此进行了测试，但确实有效。

Answer 2

试试这个。

    ABAddressBookRef addressBook = ABAddressBookCreate();
    NSArray *people = (NSArray*)ABAddressBookCopyArrayOfAllPeople(addressBook);
    for(id person in people){
         NSString *name = [NSString stringWithFormat:@"%@ %@",(NSString *)ABRecordCopyValue( person, kABPersonFirstNameProperty ),(NSString *)ABRecordCopyValue( person, kABPersonLastNameProperty )];
    //fetch multiple phone nos.
        ABMultiValueRef multi = ABRecordCopyValue(person, kABPersonPhoneProperty);
        for (CFIndex j=0; j < ABMultiValueGetCount(multi); j++) {
            NSString* phone = (NSString*)ABMultiValueCopyValueAtIndex(multi, j);
            [numbersArray addObject:phone];
            [phone release];
        }

          /fetch multiple email ids.
        ABMultiValueRef multiemail = ABRecordCopyValue(person, kABPersonEmailProperty);
        for (CFIndex j=0; j < ABMultiValueGetCount(multiemail); j++) {
             NSString* email = (NSString*)ABMultiValueCopyValueAtIndex(multiemail, j);
             NSLog(@"Email=%@",email);
        }
    }

你必须在使用之前分配你的数组。在viewDidLoad方法中为alloc array

写这个

           numbersArray=[[NSMutableArray alloc] init];