地址簿在cellForRowAtIndexPath

Question

我成功添加＆＃34; firstName＆＃34;，＆＃34; lastName＆＃34;，＆＃34; phone＆＃34;来自NSMutableDictionary的地址簿联系方式。

现在我想在表格视图中显示它：＆＃34; firstName＆＃34; +＆＃34; lastName＆＃34;但我们可以访问此联系人的号码。也许我必须创建NSObject？

这是我的代码：

- (void)getContacts:(ABAddressBookRef)addressBook
{
    NSArray *allData = CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));
    NSInteger contactCount = [allData count];

    for (int i = 0; i < contactCount; i++) {
        ABRecordRef person = CFArrayGetValueAtIndex((__bridge CFArrayRef)allData, i);

        NSString *firstName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonFirstNameProperty));
        NSString *lastName  = CFBridgingRelease(ABRecordCopyValue(person, kABPersonLastNameProperty));

        NSMutableDictionary *dictionary = [NSMutableDictionary dictionary];
        if (firstName) {
            dictionary[@"firstName"] = firstName;
        }
        if (lastName) {
            dictionary[@"lastName"]  = lastName;
        }

        ABMultiValueRef phones = ABRecordCopyValue(person, kABPersonPhoneProperty);
        CFIndex phoneNumberCount = ABMultiValueGetCount(phones);

        if (phoneNumberCount > 0) {
            NSString *phone = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phones, 0));
            dictionary[@"phone"] = phone;
        }

        // or if you wanted to iterate through all of them, you could do something like:
        //
        // for (int j = 0; j < phoneNumberCount; j++) {
        //      NSString *phone = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phones, j));
        //
        //     // do something with `phone`
        // }

        if (phones) {
            CFRelease(phones);
        }

        self.test = [dictionary allValues];
        NSLog(@"%@", self.test);
    }
}

当我记录self.test（NSArray）时，我有类似的东西：

2015-07-30 00:00:51.842 ChillN[4764:59116] (
    John,
    "888-555-5512",
    Appleseed
)
2015-07-30 00:00:51.843 ChillN[4764:59116] (
    Anna,
    "555-522-8243",
    Haro
)

我想在我的手机上显示：＆＃34; John Appleseed＆＃34;，＆＃34; Anna Haro＆＃34;但仍然存储此联系人的号码。

我不知道下一步该做什么......