将值与结构成员进行比较的问题

时间:2013-05-29 10:28:13

标签: c++ struct comparison const

这个问题是后续行动: Redefinition and Enumerator

我的C ++编译器提供以下警告和错误:

1>forgelib\source\socket.cpp(145): warning C4832: token '.' is illegal after UDT 'Forge::AddressFamily'
1>          forgelib\include\forge\socket.h(70) : see declaration of 'Forge::AddressFamily'
1>forgelib\source\socket.cpp(145): error C2275: 'Forge::AddressFamily' : illegal use of this type as an expression
1>          forgelib\include\forge\socket.h(70) : see declaration of 'Forge::AddressFamily'
1>forgelib\source\socket.cpp(145): error C2228: left of '.INet' must have class/struct/union

这是socket.cpp(145):

void Forge::InternetHost::validHostEntity(hostent* he) {
    if (he->h_addrtype != AddressFamily.INet || he->h_length != 4) { // <--145
        throw new Forge::SocketException("Address family mismatch.");
    }
}

这是定义:

struct AddressFamily {
    static const Forge::Int Unspecified = AF_UNSPEC;
    static const Forge::Int UNIX = AF_UNIX;
    static const Forge::Int INet = AF_INET;
    static const Forge::Int IPX = AF_IPX;
    static const Forge::Int AppleTalk = AF_APPLETALK;
    static const Forge::Int INet6 = AF_INET6;
};

我错过了一些非常明显的东西吗?

3 个答案:

答案 0 :(得分:2)

INetAddressFamily的静态成员,因此您需要

AddressFamily::INet

答案 1 :(得分:2)

应该是

he->h_addrtype != AddressFamily::INet

因为INet是struct的静态成员。

答案 2 :(得分:2)

您应该尝试这样访问静态成员:

AddressFamily::INet