在方法上使用synchronized关键字一次只允许一个线程执行该方法,但EDT可以同时处理将在该方法中运行的多个“事件”。请参阅下面的示例代码以进行演示。单击测试按钮时,输出为:
0 before dialog, EDT=true
1 before dialog, EDT=true
(click OK button for 1 here)
1 after dialog, EDT=true
(click OK button for 0 here)
0 after dialog, EDT=true
我正在寻找的方法是一次只允许一个EDT事件在test()方法中处于活动状态,这样输出就可以
0 before dialog, EDT=true
(click OK button for 0 here)
0 after dialog, EDT=true
1 before dialog, EDT=true
(click OK button for 1 here)
1 after dialog, EDT=true
似乎有人必须先解决这个问题。我认为可以在方法的开头编写某种锁定对象,或者包装方法,但是懒惰,宁愿不重新发明轮子。
我的测试用例:
package test1;
import javax.swing.JDialog;
import javax.swing.JOptionPane;
import javax.swing.SwingUtilities;
import javax.swing.SwingWorker;
public class EDTSyncTest extends javax.swing.JFrame {
private static final Object locker = new Object();
private int counter;
public EDTSyncTest() {
initComponents();
}
private synchronized void test() {
int l_id = counter++;
logit("" + l_id + " before dialog, EDT=" + SwingUtilities.isEventDispatchThread());
JOptionPane l_pane = new JOptionPane("test id " + l_id);
JDialog l_diag = l_pane.createDialog(this, "test");
l_diag.setModal(true);
l_diag.setVisible(true);
logit("" + l_id + " after dialog, EDT=" + SwingUtilities.isEventDispatchThread());
}
private void startTest() {
new Delayer().execute();
test();
}
private static void logit(String a_msg) {
System.out.println(a_msg);
}
private class Delayer extends SwingWorker<Object, Object> {
@Override
protected Object doInBackground() throws Exception {
Thread.sleep(2000);
return null;
}
@Override
protected void done() {
test();
}
}
private void initComponents() {
jButton1 = new javax.swing.JButton();
setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE);
getContentPane().setLayout(new java.awt.FlowLayout());
jButton1.setText("Test");
jButton1.setName("jButton1"); // NOI18N
jButton1.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed(java.awt.event.ActionEvent evt) {
jButton1ActionPerformed(evt);
}
});
getContentPane().add(jButton1);
pack();
}
private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {
startTest();
}
public static void main(String args[]) {
java.awt.EventQueue.invokeLater(new Runnable() {
public void run() {
new EDTSyncTest().setVisible(true);
}
});
}
protected javax.swing.JButton jButton1;
}
答案 0 :(得分:5)
好的,好的,这是我的答案,在millimoose的支持下指导:D
让我们从这些观察开始:
因此,模态对话框无法阻止回放事件,否则会导致整个用户界面无响应;然后,它如何在不阻止挥动事件的情况下阻止?
模态对话框运行自己的事件调度循环。然后,代码执行调用图(在完成SwingWorker之后在EDT线程上运行完全)如下所示:
-> done (process FIRST done)
-> 0/before
-> modal dialog event loop (process NEXT done)
-> 1/before
-> modal dialog event loop (TOP DIALOG)
<- OK PRESSED
<- 1/after
<- OK PRESSED
<- 0/after
<- back to normal EDT event loop
因此,模态对话框在运行时仍处理着摆动事件,但是以“递归”的方式。
答案 1 :(得分:1)
我刚刚弄清楚自己,但正如@millimoose所评论的那样:
test()
方法没有被同时调用,只是递归调用。
稍微修改一下您的代码,您会看到:
logit("" + l_id + " before dialog, EDT="
+ SwingUtilities.isEventDispatchThread());
new Throwable().printStackTrace(System.out);
输出:
0 before dialog, EDT=true
java.lang.Throwable
at EDTSyncTest.test(EDTSyncTest.java:22)
at EDTSyncTest.startTest(EDTSyncTest.java:35)
at EDTSyncTest.jButton1ActionPerformed(EDTSyncTest.java:75)
at EDTSyncTest.access$1(EDTSyncTest.java:74)
at EDTSyncTest$1.actionPerformed(EDTSyncTest.java:66)
at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
/* ... */
at java.awt.EventDispatchThread.run(Unknown Source)
1 before dialog, EDT=true
java.lang.Throwable
at EDTSyncTest.test(EDTSyncTest.java:22)
at EDTSyncTest.access$0(EDTSyncTest.java:17)
at EDTSyncTest$Delayer.done(EDTSyncTest.java:51)
at javax.swing.SwingWorker$5.run(Unknown Source)
/* ... */
at java.awt.Dialog.setVisible(Unknown Source)
at EDTSyncTest.test(EDTSyncTest.java:27)
at EDTSyncTest.startTest(EDTSyncTest.java:35)
at EDTSyncTest.jButton1ActionPerformed(EDTSyncTest.java:75)
at EDTSyncTest.access$1(EDTSyncTest.java:74)
at EDTSyncTest$1.actionPerformed(EDTSyncTest.java:66)
at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
/* ... */
at java.awt.EventDispatchThread.run(Unknown Source)
1 after dialog, EDT=true
0 after dialog, EDT=true