Question

我遇到以下SQL查询的where语句时遇到问题：

select distinct
  [columns]
from ifsapp.customer_order_inv_head coih
left outer join ifsapp.identity_invoice_info iii
  on coih.company = iii.company
  and coih.identity = iii.identity
  and iii.party_type_db = 'CUSTOMER'
left outer join ifsapp.customer_info_address cia
  on coih.identity = cia.customer_id
  and cia.address_id = '1' 
left outer join ifsapp.customer_info_comm_method cicm
  on coih.identity = cicm.customer_id
  and cicm.address_id = '1'
where coih.invoice_date between to_date('&date_from', 'dd/mm/yyyy') and to_date('&date_to',        'dd/mm/yyyy')
  and iii.group_id not in ('1', '2', '3', '4', '5', '6', '7', '8', '9')
  and iii.pay_term_id <> 'SO'
  and ifsapp.fb_dev_utils_api.is_einvoice_customer(coih.identity) = 'FALSE'
  and ifsapp.fb_dev_utils_api.is_edi_customer(coih.identity) = 'FALSE'
  and coih.net_amount >= ('&Value')
  and upper(cicm.name) not like upper(nvl('&Optout', 'blank'))
  and upper(iii.group_id) like upper(nvl('&Cust_Group', '%'))
  and upper(coih.company) like upper(nvl('&Company', '%'))

以上工作正常（如果有点慢），但我也想仅在iii.group_id = '10'时排除coih.contract not like 'S%'，但我无法正确理解语法。我尝试过以下方法：

or (coih.contract not like 'S%' and iii.group_id = '10')

非常感谢任何帮助。

Answer 1

而不是：

OR (coih.contract NOT LIKE 'S%' AND iii.group_id = '10')

试试这个：

AND NOT (coih.contract LIKE 'S%' AND iii.group_id = '10')

通过这种方式，它将查看group_id是否等于10且合同不是以'S'开头。

Answer 2

你有点走上正轨。但是where语句是关于包含的内容，而不是排除。您想要包含以下记录：

and (coih.contract like 'S%' or iii.group_id <> '10')

您可能会发现此表单更容易理解：

and not (coih.contract not like 'S%' and iii.group_id = '10')

顺便说一下，这假设两个变量不采用NULL值。

oracle sql条件where语句

2 个答案: