Question

使用下表。我正在尝试获取Party_ID。我将只有NEW_ORG_ID和ORIGINAL_ID。

使用NEW_ORG_ID，我想获得具有MAX（USR_CRTE_TS）的PARTY_ID。除非，ORIGINAL_ID也要匹配。然后，我希望NEW_ORG_ID和ORIGINAL_ID匹配的PARTY_ID。

PARTY_ID          |DIRS_ID  |SUPPLIER_ID|ORIGINAL_ID|TRIANGLE_ID|NEW_ORG_ID|USR_CRTE_TS        |
------------------|---------|-----------|-----------|-----------|----------|-------------------|
5385606962        |476800490|5385606962 |NULL       |NULL       |69214683  |2018-09-27 04:56:13|
69214683          |476800490|NULL       |2740793553 |NULL       |69214683  |2018-09-27 04:54:15|

我尝试了以下方法。请记住，仅在此示例中，我对NEW_ORG_ID和ORIGINAL_ID进行了硬编码。在实际示例中，查询的另一部分提供了NEW_ORG_ID和ORIGINAL_ID。

    SELECT DISTINCT PARTY_ID 
FROM UNIQUE_IDS UNQ 
WHERE   
( 
        CASE
            WHEN ( 
                    SELECT ts.PARTY_ID
                    FROM UNIQUE_IDS ts 
                    WHERE (ts.NEW_ORG_ID = '69214683' AND ts.ORIGINAL_ID = '2740793553') 
                 ) IS NOT NULL
            THEN 
                (
                    SELECT ts.PARTY_ID 
                    FROM UNIQUE_IDS ts 
                    WHERE (ts.NEW_ORG_ID = '69214683' AND ts.ORIGINAL_ID = '2740793553') 
                )
            ELSE 
                (
                    SELECT ts.PARTY_ID
                    FROM UNIQUE_IDS ts 
                    WHERE ts.NEW_ORG_ID = '69214683'
                    AND ts.USR_CRTE_TS = (  
                                            SELECT MAX(ts.USR_CRTE_TS) 
                                            FROM UNIQUE_IDS ts 
                                            WHERE ts.NEW_ORG_ID = '69214683'
                                        )--xref.SBL_GLOB_CSTMR_ID)
                )
        END
) = UNQ.NEW_ORG_ID

;

Answer 1

您可以使用ROW_NUMBER()分析函数来获得标记为1的“最佳”匹配（首先由ORIGINAL_ID，然后由USR_CRTE_TS），然后对其进行过滤：< / p>

SELECT PARTY_ID
FROM   (
            SELECT  PARTY_ID,
                    USR_CRTE_TS,  
                    ROW_NUMBER() OVER (
                        PARTITION BY PARTY_ID 
                        ORDER BY     CASE ORIGINAL_ID 
                                         WHEN '2740793553' THEN 0 
                                         ELSE 1 
                                     END,
                                     USR_CRTE_TS DESC
                    ) RN
            FROM    UNIQUE_IDS
            WHERE   NEW_ORG_ID = '69214683'
        )
WHERE   RN = 1

如果USR_CRTE_TS可以是NULL，则在末尾添加另一个条件以符合您的条件：

AND     (ORIGINAL_ID = '2740793553' OR USR_CRTE_TS IS NOT NULL)

在其他位置选择条件

您可以使用WITH子句来逐步构建查询。因此，假设您已经具有选择两个“参数”的工作逻辑，然后将其放在with子句中，如下所示：

WITH CRIT(SEL_ORG_ID, SEL_ORIGINAL_ID) AS (
    SELECT '69214683', '2740793553' FROM DUAL -- this is just an example
)

...，然后像这样继续查询：

), BASE AS (
    SELECT  UI.PARTY_ID,
            UI.USR_CRTE_TS,
            UI.ORIGINAL_ID,
            CRIT.SEL_ORIGINAL_ID,
            ROW_NUMBER() OVER (
                PARTITION BY UI.PARTY_ID 
                ORDER BY     CASE UI.ORIGINAL_ID 
                                 WHEN CRIT.SEL_ORIGINAL_ID THEN 0 
                                 ELSE 1 
                             END,
                             UI.USR_CRTE_TS DESC
            ) RN
    FROM    UNIQUE_IDS UI,
            CRIT
    WHERE   UI.NEW_ORG_ID = CRIT.SEL_NEW_ORG_ID
)
SELECT PARTY_ID
FROM   BASE
WHERE  RN = 1
AND    (ORIGINAL_ID = SEL_ORIGINAL_ID OR USR_CRTE_TS IS NOT NULL)

Answer 2

我将row_number()用于条件排序：

select party_id 
  from (
    select party_id, 
           row_number() over (order by case when original_id = '2740793553' then 1 end, 
                                       usr_crte_ts desc) rn
      from unique_ids unq
      where new_org_id = '69214683')
  where rn = 1

^{dbfiddle demo}

如果original_id匹配，则行具有更高的优先级。第二优先级最高usr_crte_ts。最后，我们排在第一位。

有条件的在哪里？

2 个答案:

在其他位置选择条件