Question

我有一套像（669256.02,6117662.09,669258.61,6117664.39,669258.05,6117665.08），我需要迭代，如

    for x,y in (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
        print (x,y)

会打印

    669256.02 6117662.09
    669258.61 6117664.39
    669258.05 6117665.08

im on Python 3.3 btw

Answer 1

您可以使用迭代器：

>>> lis = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> it = iter(lis)
>>> for x in it:
...     print (x, next(it))
...     
669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08

Answer 2

>>> nums = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> for x, y in zip(*[iter(nums)]*2):
        print(x, y)


669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08

Answer 3

grouper食谱部分中的itertools示例应该可以帮助您： http://docs.python.org/3.3/library/itertools.html#itertools-recipes

from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return zip_longest(*args, fillvalue=fillvalue)

然后您将使用：

for x, y in grouper(my_set, 2, 0.0): ## Use 0.0 to pad with a float
    print(x, y)

在python中一次迭代列表的两个值

3 个答案: