Question

我想用bash脚本编辑一堆文件。首先，我需要文件的单一路径以及计数器。到目前为止，我想出了这个：

let n=0
array=(`pwd`"/worker/worker*/conf/logfilefilter-worker*.xml")
for i in "${array[@]}"; do
  let "c += 1"
  echo $i
  echo $c
  # here comes the edit stuff.
done

但是这个循环只运行一次：

[mles@sagnix etl-i_test]$ ./iprog_new --test
/home/devel/mles/etl-i_test/worker/worker01/conf/logfilefilter-worker01.xml     /home/devel/mles/etl-i_test/worker/worker02/conf/logfilefilter-worker02.xml /home/devel/mles/etl-i_test/worker/worker03/conf/logfilefilter-worker03.xml /home/devel/mles/etl-i_test/worker/worker04/conf/logfilefilter-worker04.xml /home/devel/mles/etl-i_test/worker/worker05/conf/logfilefilter-worker05.xml /home/devel/mles/etl-i_test/worker/worker06/conf/logfilefilter-worker06.xml /home/devel/mles/etl-i_test/worker/worker07/conf/logfilefilter-worker07.xml /home/devel/mles/etl-i_test/worker/worker08/conf/logfilefilter-worker08.xml
1

循环如何通过文件一个接一个地运行？

Answer 1

此

array=(`pwd`"/worker/worker*/conf/logfilefilter-worker*.xml")

只是一个元素，因为文件名通配（对于*）在引用的字符串中被抑制。然后在"${array[@]}"中，单个元素得到了全局扩展，但由于双引号保留为单个字符串，所有文件名以空格分隔。确实

array=(`pwd`/worker/worker*/conf/logfilefilter-worker*.xml)

或

for i in ${array[@]}; do  # no double quotes

工作得更好？另一方面，如果没有像数组这样的bashims更便携的解决方案呢？迭代文件的规范方法是

for file in $PWD/worker/worker*/conf/logfilefilter-worker*.xml; do
   echo "$file"
done

循环遍历bash脚本中的文件

1 个答案: