我有一个名为locations.txt
的txt文件:
location-1a
location-2c
location-3d
location-4
location-5a
...
我希望在for循环中遍历locations.txt
文件,每个位置应用于5个节点,然后应使用下一个位置。因此,例如,我要运行以下命令,
server create --location location-1a node-1
server create --location location-1a node-2
server create --location location-1a node-3
server create --location location-1a node-4
server create --location location-1a node-5
server create --location location-2c node-6
.....
到目前为止,我只有以下名为script.sh
的脚本,它带有cli的参数。我无法按照自己的意愿更改位置。
mapfile -t locationArr < ~/Documents/files/locations.txt
serverCounter=1
locationCounter=1
counter=1
counter=1
for (( i = 1; i <= $1; i++ ))
do
server create --location $locationArr[$locationCounter] node-$i
counter=$((counter+1))
if [ $counter == 5 ]
then
counter=1
locationCounter=$((locationCounter+1))
done
我想要类似的东西
if counter == 5:
counter=0
nextline
例如,如果我运行script.sh 11
,我想要以下结果,
server create --location location-1a node-1
server create --location location-1a node-2
server create --location location-1a node-3
server create --location location-1a node-4
server create --location location-1a node-5
server create --location location-2c node-6
server create --location location-2c node-7
server create --location location-2c node-8
server create --location location-2c node-9
server create --location location-2c node-10
server create --location location-3d node-11
如何在for循环中遍历location.txt文件?我应该将文本文件转换为某种列表变量吗?
答案 0 :(得分:2)
这是我的尝试
counter=1
while IFS= read -r line
do
for (( i=1; i <= 5 && $counter <= $1; i++ ))
do
server create --location $line node-$counter
counter=$((counter+1))
done
done < ~/Documents/files/locations.txt
输出为11:
server create --location location-1a node-1
server create --location location-1a node-2
server create --location location-1a node-3
server create --location location-1a node-4
server create --location location-1a node-5
server create --location location-2c node-6
server create --location location-2c node-7
server create --location location-2c node-8
server create --location location-2c node-9
server create --location location-2c node-10
server create --location location-3d node-11
答案 1 :(得分:1)
概述:
locations.txt
读取位置的外循环上述的一种实现方式:
max=${1}
curr=1
while read -r location
do
for i in {1..5}
do
echo "server create --location ${location} node-${curr}"
curr=$((curr+1))
[ ${curr} -gt ${max} ] && break 2
done
done < locations.txt
使用max=${1}=11
进行测试:
server create --location location-1a node-1
server create --location location-1a node-2
server create --location location-1a node-3
server create --location location-1a node-4
server create --location location-1a node-5
server create --location location-2c node-6
server create --location location-2c node-7
server create --location location-2c node-8
server create --location location-2c node-9
server create --location location-2c node-10
server create --location location-3d node-11
OP可以为max
是大于0的整数添加附加检查。
答案 2 :(得分:1)
完成单循环,没有Bashism POSIX语法:
#!/usr/bin/env sh
i=0
while [ $i -lt "$1" ] && {
[ $((i % 5)) -ne 0 ] || IFS= read -r line || [ "$line" ]
}; do
server create --location "$line" "node-$((i = i + 1))"
done <locations.txt