我正在尝试使用OpenCV 2.4.5和Visual Studio 2010 Express创建简单的一维条形码阅读器。
到目前为止,这是我的代码:
//define Image path:
char* imageName = "D:\\Barcode Reader\\test3.jpg";
cv::Mat src = cv::imread(imageName);
if( !src.data )
{ return -1; }
//convert image to grayscale img:
cv::Mat gray_image;
cvtColor (src, gray_image, CV_BGR2GRAY);
unsigned char color;
unsigned char next_black_color = 0;
unsigned char next_white_color = 0;
int buffer[500];
float factor = (float)gray_image.cols / (float)required_width;
//start to search for pixels from left to right (in the middle of the img):
unsigned char *position = gray_image.ptr(gray_image.rows/2,0);
//iterate through the whole image length:
for (int col = 1; col <= gray_image.cols; col++)
{
//...and store the pixel value in color variable for possible output (which would be like 0-127 for black colors and 127-255 for white colors:
color = *position;
position++;
//check the pixel value ( < 127 everything bellow has dark color):
if (color < 127)
{
//...and after each position checked, go to next pixel and save the number of occurences of black pixels:
next_black_color++;
buffer[col] = next_black_color;
std::cout << col << ": " << buffer[col] << " ";
}
else
{
//set the counter variable to null for the next occurence of black pixel:
next_black_color = 0;
}
//the same goes for white pixels:
if (color > 127)
{
next_white_color++;
buffer[col] = next_white_color;
std::cout << col << ": " << buffer[col] << " ";
}
else
{
next_white_color = 0;
}
}
//show the results:
std::cout<<" Number of pixels in width = " << src.cols << std::endl <<
"Number of pixels in height = " << src.rows << std::endl;
cv::imshow("Normal Image", src);
cv::imshow("Gray Image", gray_image);
cv::waitKey(0);
return 0;
测试图像是100x100px图像,黑色和白色像素按以下顺序排列 (描述为二进制代码以便更好地理解:1 =黑色,0 =白色) 10100&lt; ..白色像素..&gt; 00101
我这样做的原因很简单......
假设我有一个81像素长的UPC条形码。 但是,我加载的图像长度超过1000像素。
要应用检测并将我加载的图像与UPC图案进行比较,我必须首先缩放加载的图像以校正像素值。 (我使用“缩放”这个词......因为如果我只是“调整”我的图像......它会切掉919像素,使检测不可能。)
我知道加载的图像是UPC模式的因子12,34(接近12 ......我现在不关心正确的值...我所关心的只是实现目前......)
我使用此实现遇到以下问题:
出现的内容如下:
____[Array]____
Position | Occurence
1 ......... 1 (First position with first black pixel)
2 ......... 1 (white)
3 ......... 1 (black)
4 ......... 1 (white pixels until next black pixel appears..)
5 ......... 2 (___Problem here!___ ... should be 94!)
6 ......... 3 .
. ......... . .
100 ....... 100(end)
但它应该是:
____[Array]____
Position | Occurence
1 ......... 1 (First position with first black pixel)
2 ......... 1 (white)
3 ......... 1 (black)
4 ......... 94 (count all white pixels until black appears again)
5 ......... 1 (black)
6 ......... 1 (white)
7 ......... 1 (black) -> end
我希望我能提供足够的答案信息。
请帮我修正我的代码。 最好的祝福 的Ondrej
答案 0 :(得分:1)
我认为你应该重做你的周期。这是正确的,但太复杂了。您的代码存在问题:
buffer[col] = next_black_color;
变量 col 总是在增加,因此更新后的颜色计数会添加到数组中的新插槽中。在您的示例中,您不能在位置5处拥有97,因为根据您的代码,在位置5处,您只处理了5个像素。
您的代码的另一个小问题是,您有两个互斥的条件。如果颜色&lt; 127和颜色&gt; 127.首先,如果颜色是&lt; 127,else表示颜色> = 127。等号很重要!如果所有颜色都是127,你的代码就会失败。
以下是算法的草稿:
int arr[] = {0,0,180,180,180,180,180,180,180,180,180,0,0,0};
int size = 14;
bool last_dark = false;
bool current_dark = false;
if(arr[0] < 127){
last_dark = true;
}
int counter = 0;
for(int i = 0; i < size; i++){
if(arr[i] < 127){
current_dark = true;
} else {
current_dark = false;
}
// is current pixel same shade as last?
if(last_dark == current_dark){
counter++;
} else {
cout << counter << endl;
counter = 1; // the last color is already processed
}
last_dark = current_dark;
}
// following line is important to get the last count
cout << counter << endl;
绝不是完整的。你必须适应你的需要。在最后一个if中,我们无法直接比较last和current值,因为120和12都是暗的,但不是相同的值。在你的代码中用适当的向量分配替换cout,并且不要忘记循环外的那个。 ;)
问候,
jnovacho