我有一个类似的json字符串,
{"objectType" : "Subscriber", "objectList":[{"firstName":"name1","email":"email@example.com","address":"exampleAddress"},{"firstName":"name2","email":"email2@example.com","address":"exampleAddress2"}]}
我需要在我的C#代码中解析它。我试过了,
JavaScriptSerializer json_serializer = new JavaScriptSerializer();
object routes_list = json_serializer.DeserializeObject(myjson here);
但是我无法遍历“objectList”数组。怎么做?
答案 0 :(得分:29)
var jsonObj = new JavaScriptSerializer().Deserialize<RootObj>(json);
foreach (var obj in jsonObj.objectList)
{
Console.WriteLine(obj.address);
}
public class ObjectList
{
public string firstName { get; set; }
public string email { get; set; }
public string address { get; set; }
}
public class RootObj
{
public string objectType { get; set; }
public List<ObjectList> objectList { get; set; }
}
提示:您可以使用this site将您的json字符串转换为c#classes
修改强>
使用Json.Net
dynamic jsonObj = JsonConvert.DeserializeObject(json);
foreach (var obj in jsonObj.objectList)
{
Console.WriteLine(obj.address);
}
答案 1 :(得分:3)
var routes_list = (Dictionary<string, object>)json_serializer.DeserializeObject(myjson);
foreach (var record in routes_list)
{
Console.WriteLine(record);
}
答案 2 :(得分:1)
这对我有用,基本上转换为JSON到YAML
string JSONDeserialized {get; set;}
public int indentLevel;
private bool JSONDictionarytoYAML(Dictionary<string, object> dict)
{
bool bSuccess = false;
indentLevel++;
foreach (string strKey in dict.Keys)
{
string strOutput = "".PadLeft(indentLevel * 3) + strKey + ":";
JSONDeserialized+="\r\n" + strOutput;
object o = dict[strKey];
if (o is Dictionary<string, object>)
{
JSONDictionarytoYAML((Dictionary<string, object>)o);
}
else if (o is ArrayList)
{
foreach (object oChild in ((ArrayList)o))
{
if (oChild is string)
{
strOutput = ((string)oChild);
JSONDeserialized += strOutput + ",";
}
else if (oChild is Dictionary<string, object>)
{
JSONDictionarytoYAML((Dictionary<string, object>)oChild);
JSONDeserialized += "\r\n";
}
}
}
else
{
strOutput = o.ToString();
JSONDeserialized += strOutput;
}
}
indentLevel--;
return bSuccess;
}
用法
Dictionary<string, object> JSONDic = new Dictionary<string, object>();
JavaScriptSerializer js = new JavaScriptSerializer();
try {
JSONDic = js.Deserialize<Dictionary<string, object>>(inString);
JSONDeserialized = "";
indentLevel = 0;
DisplayDictionary(JSONDic);
return JSONDeserialized;
}
catch (Exception)
{
return "Could not parse input JSON string";
}