我需要创建三个子进程,每个进程从命令行参数中读取一个字符串,并将该字符串写入单个管道。然后父母将从管道中读取字符串并在屏幕上显示所有这三个字符串。我尝试用两个进程来测试,它打印两个字符串,而不是两个。
#include <stdio.h>
#include <unistd.h>
int main (int argc, char *argv[]) {
char *character1 = argv[1];
char *character2 = argv[2];
char inbuf[100]; //creating an array with a max size of 100
int p[2]; // Pipe descriptor array
pid_t pid1; // defining pid1 of type pid_t
pid_t pid2; // defining pid2 of type pid_t
if (pipe(p) == -1) {
fprintf(stderr, "Pipe Failed"); // pipe fail
}
pid1 = fork(); // fork
if (pid1 < 0) {
fprintf(stderr, "Fork Failed"); // fork fail
}
else if (pid1 == 0){ // if child process 1
close(p[0]); // close the read end
write(p[1], character1, sizeof(&inbuf[0])); // write character 1 to the pipe
}
else { // if parent, create a second child process, child process 2
pid2 = fork();
if (pid2 < 0) {
fprintf(stderr, "Fork Failed"); // fork fail
}
if (pid2 = 0) { // if child process 2
close(p[0]); // close the read end
write(p[1], character2, sizeof(&inbuf[0])); // write character 2 to the pipe
}
else { // if parent process
close(p[1]); // close the write end
read(p[0], inbuf, sizeof(&inbuf[0])); // Read the pipe that both children write to
printf("%s\n", inbuf); // print
read(p[0], inbuf, sizeof(&inbuf[0])); // Read the pipe that both children write to
printf("%s\n", inbuf); // print
}
}
}
答案 0 :(得分:3)
在没有更多数据要读取之前,您的代码不会继续循环。它只进行一次读取。它也不会检查read()
返回的值,但它应该。
我已将fork()
和write()
(以及错误检查)代码抽象为函数。这似乎有效:
#include <errno.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
static void child(int fd, const char *string)
{
pid_t pid = fork();
int len = strlen(string);
if (pid < 0)
{
fprintf(stderr, "%.5d: failed to fork (%d: %s)\n",
(int)getpid(), errno, strerror(errno));
exit(1);
}
else if (pid > 0)
return;
else if (write(fd, string, len) != len)
{
fprintf(stderr, "%.5d: failed to write on pipe %d (%d: %s)\n",
(int)getpid(), fd, errno, strerror(errno));
exit(1);
}
else
exit(0);
}
int main (int argc, char *argv[])
{
char inbuf[100]; //creating an array with a max size of 100
int p[2]; // Pipe descriptor array
if (argc != 4)
{
fprintf(stderr, "Usage: %s str1 str2 str3\n", argv[0]);
return 1;
}
if (pipe(p) == -1)
{
fprintf(stderr, "Pipe Failed"); // pipe fail
return 1;
}
for (int i = 0; i < 3; i++)
child(p[1], argv[i+1]);
int nbytes;
close(p[1]); // close the write end
while ((nbytes = read(p[0], inbuf, sizeof(inbuf))) > 0)
printf("%.*s\n", nbytes, inbuf); // print
return 0;
}
我每次都使用命令行多次运行命令:
./p3 'message 1' 'the second message' 'a third message for the third process'
一次运行,输出为:
the second messagemessage 1
a third message for the third process
另一方面,我得到了:
the second messagemessage 1a third message for the third process
另一方面,我得到了:
message 1
the second messagea third message for the third process
(这是在配备Intel Core i7的MacBook Pro上,运行Mac OS X 10.8.3,并使用GCC 4.7.1。)