Question

我在屏幕上绘制一个简单的矩形时遇到问题。我不知道为什么它无法绘制，我已经尝试了几件事：在背景表面上绘制它，改变函数调用的顺序等但它似乎并没有绘制任何东西。正如你所看到的，enemy（）方法应该绘制一个红色矩形，而不是什么都不绘制。否则游戏运行正常。我确信它很简单，我忽略了......令人沮丧！

import pygame
from pygame.locals import *
from pygame.time import *
from pygame.font import *
from pygame.draw import *
import sys
pygame.font.init()
pygame.init()


screen = pygame.display.set_mode((700,300))
pygame.display.set_caption('something')

#--------------------------------------------------------------------

velX = 0
velY = 0
playerx = 20
player_filename = 'player.png'
player = pygame.image.load(player_filename)
playery = 150
clock = pygame.time.Clock()

#--------------------------------------------------------------------

def draw():         
    global velX
    global velY
    global playerx
    global playery

    red = pygame.Color(255,0,0)
    black = pygame.Color(0,0,0)

    level = "1"
    background = pygame.Surface(screen.get_size())
    background = background.convert()
    background.fill((255,255,255))
    screen.blit(background, (0,0))

    playerx = playerx + velX
    playery = playery + velY
    screen.blit(player, (playerx,playery))
    font = pygame.font.Font(None, 36)
    text = font.render(level, 1, black)
    screen.blit(text, (670,10))
    pygame.display.flip()

#--------------------------------------------------------------------

def enemySquares():
    enemySurf = pygame.Surface(screen.get_size())
    red = pygame.Color(255,0,0)
    enemy = pygame.Rect(200,50,20,20)
    pygame.draw.rect(enemySurf, red, enemy, 0)

#--------------------------------------------------------------------

def collisionWithBorder():
    if playerx > 680 or playerx < 0:
        pygame.quit()
        sys.exit()
    if playery > 280 or playery < 0:
        pygame.quit()
        sys.exit()

#--------------------------------------------------------------------

def playerFunc():
    keys_down = pygame.key.get_pressed()    
    pygame.key.set_repeat(1,50)
    time = 50/1000
    global velX
    global velY
    direction = -1

    if keys_down[K_d]:
        direction = 0
    if keys_down[K_a]:
        direction = 3
    if keys_down[K_w]:
        direction = 1
    if keys_down[K_s]:
        direction = 2

    if direction == 0:
        velX = 50*time
        velY = 0
    if direction == 1:
        velY = -50*time
        velX = 0
    if direction == 2:
        velY = 50*time
        velX = 0
    if direction == 3:
        velX = -50*time
        velY = 0

#--------------------------------------------------------------------

def main(): 
    while True:

        for event in pygame.event.get():   
            if event.type == QUIT:
                pygame.quit()
                sys.exit()

        clock.tick(50)        
        collisionWithBorder()
        draw()
        playerFunc()
        enemySquares()

#--------------------------------------------------------------------

if __name__ == '__main__':
    main()

Answer 1

def enemySquares():
    enemySurf = pygame.Surface(screen.get_size())
    red = pygame.Color(255,0,0)
    enemy = pygame.Rect(200,50,20,20)
    pygame.draw.rect(enemySurf, red, enemy, 0)

上面的函数确实绘制了一个红色矩形 - 在它创建的新surace上，而不是 “屏幕”表面。

将enemySurf = ...行放在那里并更改pygame.draw.rect(enemySurf, red, enemy, 0) 至 pygame.draw.rect(screen, red, enemy, 0)要在下次调用pygame.display.flip()

时使矩形显示为apear

Pygame绘图无法正常工作

1 个答案: