我有一个Asp_Users
表和一个Resource
表。在实体框架世界中,我有一个Asp_Users
POCO和一个Resource
POCO。此外,Resource
POCO是抽象的,并且是Table-per-Hierarchy模型的一部分。 Table-per-Hierarchy模型具有抽象Resource
POCO和几个Concrete
POCO,如ILCResource
POCO和SectionResource
POCO。从Asp_Users
POCO(单边)到Resource
POCO(多边)之间存在一对多(1到0 ......)的关系。
这是我的aspnet_Users POCO的相关部分:
public partial class aspnet_Users
{
public aspnet_Users() { }
public virtual System.Guid ApplicationId { get; set; }
public virtual System.Guid UserId { get; set; }
public virtual string UserName { get; set; }
public virtual string LoweredUserName { get; set; }
public virtual string MobileAlias { get; set; }
public virtual bool IsAnonymous { get; set; }
public virtual System.DateTime LastActivityDate { get; set; }
public virtual ICollection<Resource> associatedResources { get; set; }
}
这是我对Asp_Users的映射配置
public class Aspnet_UsersMap : EntityTypeConfiguration<PerlsData.Domain.aspnet_Users>
{
public Aspnet_UsersMap()
{
this.ToTable("aspnet_Users", schemaName: "dbo");
this.HasKey(u => u.UserId);
this.Property(u => u.UserId)
.HasColumnName("UserId")
.HasDatabaseGeneratedOption(DatabaseGeneratedOption.Identity);
this.HasOptional(u => u.associatedResources);
}
}
这是我的抽象资源POCO课程的相关部分:
public abstract class Resource
{
public Resource(){
// associatedPerspectives = new HashSet<Perspective>();
}
public virtual System.Guid ResourceDatabaseID { get; set; }
public virtual string ResourceName { get; set; }
public virtual string DescriptionOfResource { get; set; }
public virtual System.Guid UserId { get; set; }
public virtual Nullable<System.Guid> DepartmentDatabaseID { get; set; }
public virtual string ResourceStatus { get; set; }
public virtual Nullable<short> isRemoved { get; set; }
public virtual Department Department { get; set; }
public virtual System.Guid UserId { get; set; }
public virtual aspnet_Users aspnet_Users { get; set; }
public virtual ICollection<ResourceOverToILCResourcesBridge> associatedResourceOverToILCResourcesBridgeEntry { get; set; }
}
这是我的资源的映射配置:
public class ResourceMap : EntityTypeConfiguration<Resource>
{
public ResourceMap()
{
this.ToTable("Resources", schemaName: "dbo");
this.Property(r => r.ResourceDatabaseID)
.HasColumnName("ResourceDatabaseID");
this.HasKey(r => r.ResourceDatabaseID);
this.Property(x => x.ResourceDatabaseID)
.HasDatabaseGeneratedOption(DatabaseGeneratedOption.Identity);
// .StoreGeneratedPattern = StoreGeneratedPattern.Identity;
this.Property(r => r.ResourceName)
.HasColumnName("ResourceName");
this.Map<PerlsData.Domain.OtherItem>(m => m.Requires("discriminator").HasValue("otheritems"))
.Map<PerlsData.Domain.Audioitem>(m => m.Requires("discriminator").HasValue("audioitems"))
.Map<PerlsData.Domain.Imageitem>(m => m.Requires("discriminator").HasValue("imageitems"))
.Map<PerlsData.Domain.Videoitem>(m => m.Requires("discriminator").HasValue("videoitems"))
.Map<PerlsData.Domain.UriItem>(m => m.Requires("discriminator").HasValue("uriitems"))
.Map<PerlsData.Domain.Documentitem>(m => m.Requires("discriminator").HasValue("documentitems"))
.Map<PerlsData.Domain.DatabaseFileItem>(m => m.Requires("discriminator").HasValue("databasefileitems"));
this.HasOptional(res => res.associatedResourceOverToILCResourcesBridgeEntry);
this.HasRequired(res => res.aspnet_Users)
.WithMany(u => u.associatedResources)
.HasForeignKey(res => res.UserId);
}
}
您能否告诉我为什么会收到以下错误?
在类型上声明的导航属性“associatedResources” “PerlsData.Domain.aspnet_Users”已配置为冲突 多重性。
请解释为什么在POCO类中创建映射后它仍为NULL。
答案 0 :(得分:6)
this.HasOptional(u => u.associatedResources);
那是错的。 HasOptional
表示0..1
你想要HasMany()
。
事实上,你可以完全摆脱那条线; EF可以从房产中找到它。
答案 1 :(得分:0)
我需要更多地了解IQueryable
和/或IEnumerable
集合以及用于检索数据的lambda表达式查询,并将它们放在前面提到的IQueryable
和/中或IEnumerable
。
我的问题是我试图在迭代IQueryable
和/或IEnumerable
集合的循环中检索特定POCO的关联。
这是有缺陷的代码(我们在迭代IQueryable
时访问关联):
resourcestempIQueryable = context.Resources;
foreach (PerlsData.Domain.Resource tempRes in resourcestempIQueryable)
{
string[] resourceRow = { tempRes.ResourceName,
tempRes.DescriptionOfResource,
tempRes.UploadDate.ToString(),
tempRes.Iconpath,
tempRes.aspnet_Users.UserName, // Error
tempRes.ResourceDatabaseID.ToString() };
tempDataTableForResources.Rows.Add(resourceRow);
}
以下是应该解决问题的正确代码:
using (PerlsData.Context context = new PerlsData.Context())
{
context.Configuration.LazyLoadingEnabled = true;
context.Configuration.ProxyCreationEnabled = true;
resourcesIEnumerable = context.Resources.ToList<PerlsData.Domain.Resource>();
var entityValuesWithFieldsToShowInAllResourcesPage = context.Resources.Select(res => new { res.ResourceName, res.DescriptionOfResource, res.UploadDate, res.Iconpath, res.aspnet_Users.UserName, res.ResourceDatabaseID });
foreach (var varForIteratingOverEntityValuesWithFieldsToShowInAllResourcesPage in entityValuesWithFieldsToShowInAllResourcesPage)
{
string[] resourceRow = {
varForIteratingOverEntityValuesWithFieldsToShowInAllResourcesPage.ResourceName,
varForIteratingOverEntityValuesWithFieldsToShowInAllResourcesPage.DescriptionOfResource,
varForIteratingOverEntityValuesWithFieldsToShowInAllResourcesPage.UploadDate.ToString(),
varForIteratingOverEntityValuesWithFieldsToShowInAllResourcesPage.Iconpath,
varForIteratingOverEntityValuesWithFieldsToShowInAllResourcesPage.UserName,
varForIteratingOverEntityValuesWithFieldsToShowInAllResourcesPage.ResourceDatabaseID.ToString()
};
tempDataTableForResources.Rows.Add(resourceRow);
}
}