Question

考虑以下问题：

$query = "
SELECT a_orders.id, a_orders.billing,
   SUM(a_order_rows.quant_refunded*a_order_rows.price*((100-a_orders.discount)*.01)) as refund_total,
   SUM(a_order_rows.quant*a_order_rows.price*((100-a_orders.discount)*.01)) as order_total 
FROM a_order_rows JOIN a_orders 
ON a_order_rows.order_id = a_orders.id 
WHERE a_order_rows.quant_refunded > 0 
GROUP BY a_orders.id, a_orders.billing 
ORDER BY a_orders.id DESC 
LIMIT 50";

SUM（）的两种用法是尝试汇总订单总额和已退款的总金额。当quant_refunded字段不为0时，它们正确地出现...例如，为了简单起见，除了主键，item_id，假设每一行都是唯一的项目）：

Table: a_order_rows
Fields: order_id, quant, quant_refunded
1, 1, 1
1, 2, 1
2, 1, 1
2, 1, 0

在“订单1”的情况下，两个聚合是不同的并且表现如预期。但对于“订单2”，这两个数字是相同的 - 这两个数字都是我期望的退款数量。似乎quant_refunded中带有“0”的行正在从order_total聚合中排除。

希望这个解释得足够彻底。如果您需要更多信息，请告诉我，我会修改。谢谢！

Answer 1

$query = "
SELECT a_orders.id, a_orders.billing,
   SUM(a_order_rows.quant_refunded*a_order_rows.price*((100-a_orders.discount)*.01)) as refund_total,
   SUM(a_order_rows.quant*a_order_rows.price*((100-a_orders.discount)*.01)) as order_total 
FROM a_order_rows JOIN a_orders 
  ON a_order_rows.order_id = a_orders.id 
GROUP BY a_orders.id, a_orders.billing 
HAVING MAX(a_order_rows.quant_refunded) > 0 
ORDER BY a_orders.id DESC 
LIMIT 50";

将其更改为HAVING子句。如果任何quant_refunded行是> 0，HAVING MAX将保留它。

SQL Sum（） - 0在字段中排除聚合行？

1 个答案: