Question

{
    "_id" : ObjectId("593fbefd0b0cbbe593cd89d3"),
    "coins" : "220",
    "reasonId" : ObjectId("593500980b0cbbe593cd722c"),
    "empId" : ObjectId("592eb2e224da300ca89b05d5"),
    "clubId" : ObjectId("592d6bea7ab7f62d58001329")
}

{
    "_id" : ObjectId("59413b170b0cbbe593cd8b46"),
    "coins" : "220",
    "reasonId" : ObjectId("593500980b0cbbe593cd722c"),
    "empId" : ObjectId("592eb2e224da300ca89b05d5"),
    "clubId" : ObjectId("592d6bea7ab7f62d58001329")
}

{
    "_id" : ObjectId("593fbefd0b0cbbe593cd89d5"),
    "reasonId" : ObjectId("5934ffb80b0cbbe593cd722a"),
    "empId" : ObjectId("5912e5747f83352face7e431"),
    "coins" : "100",
    "clubId" : ObjectId("592d6bea7ab7f62d58001329")
}

我想根据clubId对单个empId的硬币求和。员工的硬币应仅基于一个俱乐部，如何对此进行聚合？

Answer 1

让我们假设您的收藏品是＆＃34;员工＆＃34;但首先将硬币转换为字符串

db.employee.aggregate(
{
   $match:{
        "empId" : ObjectId("5912e5747f83352face7e431")
   }
},
{
   $group:{
        _id: "$clubId",
        sumCoins : {$sum: "$coins"}
   }
}
)

相同字段值的$ sum

1 个答案: