Question

我一直很头疼，如何将图像上传到服务器。这对我来说是新任务。但对我来说很困惑。我在stackoverflow上搜索并用google搜索。但是我遇到了问题。

我的目的是从sdcard上传照片并从相机拍照并上传到服务器。

在ios中，这个任务已经完成，在ios php中得到这种类型：当发布php方面简单点击此信息。

并打印像这样;

$filedata = $_FILES['photos'];
$f = fopen(time().".txt",'wb');
fwrite($f, print_r($_REQUEST,true));
fclose($f);

   [photos] => Array
        (
            [name] => game.png
            [type] => image/png
            [tmp_name] => /tmp/phpiQHIXQ
            [error] => 0
            [size] => 1664972
        )

我做了什么。

   // yourSelectedImage is the bitmap image.
    public void SaveImage() throws Exception {
            try {
                 String url = "http://test.com/uploadImage.php";
                ByteArrayOutputStream bos = new ByteArrayOutputStream();
                yourSelectedImage.compress(CompressFormat.PNG, 75, bos);
                byte[] data = bos.toByteArray();
                HttpClient httpClient = new DefaultHttpClient();
                HttpPost postRequest = new HttpPost(url);

                ByteArrayBody bab = new ByteArrayBody(data, "image/jpeg");

                MultipartEntity reqEntity = new MultipartEntity(
                        HttpMultipartMode.BROWSER_COMPATIBLE);
                reqEntity.addPart("photos", bab);

                postRequest.setEntity(reqEntity);
                HttpResponse response = httpClient.execute(postRequest);
                BufferedReader reader = new BufferedReader(new InputStreamReader(
                        response.getEntity().getContent(), "UTF-8"));
                String sResponse;
                StringBuilder s = new StringBuilder();

                while ((sResponse = reader.readLine()) != null) {
                    s = s.append(sResponse);
                }
                System.out.println("Response: " + s);
            } catch (Exception e) {
                // handle exception here
                Log.e(e.getClass().getName(), e.getMessage());
            }
        }

在Php Server中，得到这样的

$ filedata = $ _FILES ['photos'];

并在php中完成了进一步的功能。

但是我没有使用httppost发布到文件结构的多部分类型，其中文件包括图像名称，图像类型，临时名称等。

编辑：

我有改变一点代码：，但未能发布图像文件信息php服务器，用户名ok但是图像文件信息无法发布。在这种情况下，Image在服务器上成功保存，我无法获取有关php服务器的信息图像。

以下是代码：

public class UploadImageHttpPost {

String testpath="/mnt/sdcard/14111.jpg";
String url = "http://test.com/uploadImage.php";

public static void sendPost(String url, String imagePath,String userId)
        throws IOException, ClientProtocolException {
    Log.w("TAG", "Start Upload" );
    Log.w("TAG", "URL-> "+url );
    Log.w("TAG", "Image Path-> "+imagePath );
    Log.w("TAG", "User Id-> "+userId );
    String responseBody;

    MultipartEntity entity = new MultipartEntity(
            HttpMultipartMode.BROWSER_COMPATIBLE);

    File file = new File(imagePath);
    FileBody encFile = new FileBody(file,"image/jpeg");
    Log.w("TAG", "image file-> "+encFile );
    entity.addPart("photos", encFile);
    entity.addPart("UserId", new StringBody(userId));
    HttpPost request = new HttpPost(url);
    request.setEntity(entity);

    HttpClient client = new DefaultHttpClient();

    ResponseHandler<String> responsehandler = new BasicResponseHandler();
    responseBody = client.execute(request, responsehandler);

    if (responseBody != null && responseBody.length() > 0) {
        Log.w("TAG", "Response from image upload->" + responseBody);

    }
}

我喜欢这个：

Array
(
    [UserId] => 914
)

但是下面的部分缺失意味着我没有得到，多部分帖子方法中是否有任何遗漏的代码请检查上面的java代码：

[photos] => Array
        (
            [name] => game.png
            [type] => image/png
            [tmp_name] => /tmp/phpiQHIXQ
            [error] => 0
            [size] => 1664972
        )

请你纠正我，如何发布php，上面的图片信息。

Answer 1

试试这个：

File file = new File(_filePath);
MultipartEntity multipart = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
multipart.addPart("file", new FileBody(file));

DefaultHttpClient httpClient = new DefaultHttpClient();

HttpResponse res;
URI uri = new URI(url.php);


HttpPost methodpost = new HttpPost(uri);
methodpost.addHeader("pragma","no-cache");
methodpost.setEntity(multipart);
res = httpClient.execute(methodpost);

InputStream data = res.getEntity().getContent();

当然，要完成你需要的东西。

希望这有帮助。

Answer 2

使用Multipart实体上传图片

    File file1 = null;
    FileBody bin1 = null;    

    HttpPost postRequest = new HttpPost(url);

      // uri for your image path   
                   if(uri != null)
                   {   
                       file1 = new File(getPath(uri));

                       bin1 = new FileBody(file1);
                   }


           MultipartEntity reqEntity = new MultipartEntity();



                   if(bin1!=null)
                       reqEntity.addPart("profile_image", bin1);


                   post.setEntity(reqEntity);


                     HttpResponse httpResponse = client.execute(post);

                     int mResponse_code =  httpResponse.getStatusLine().getStatusCode();


                     resEntity = httpResponse.getEntity();



                     response = EntityUtils.toString(resEntity);

解析你的json回应。这是非常简单的方式。

如何使用Multipart将图像上传到php服务器

2 个答案: