这个地理空间T-SQL代码的C#等价物是什么?
DECLARE @g geography;
DECLARE @h geography;
SET @g = geography::STGeomFromText('POLYGON((-122.358 47.653, -122.348 47.649, -122.348 47.658, -122.358 47.658, -122.358 47.653))', 4326);
SET @h = geography::Point(47.653, -122.358, 4326)
SELECT @g.STIntersects(@h)
我试图使用SqlGeometry
数据类型在多边形中找到一个点 - 并且可以使用上面的T-SQL;但我不明白如何实现等效的C#代码。
答案 0 :(得分:9)
试试这个:
public bool OneOffSTIntersect()
{
var g =
Microsoft.SqlServer.Types.SqlGeography.STGeomFromText(
new System.Data.SqlTypes.SqlChars(
"POLYGON((-122.358 47.653, -122.348 47.649, -122.348 47.658, -122.358 47.658, -122.358 47.653))"), 4326);
// suffix "d" on literals below optional but explicit
var h = Microsoft.SqlServer.Types.SqlGeography.Point(47.653d, -122.358d, 4326);
// rough equivalent to SELECT
System.Console.WriteLine(g.STIntersects(h));
// Alternatively return from a C# method or property (get).
return g.STIntersects(h);
}
MSDN的SqlGeography Methods页面链接到T-SQL中关键调用的每个C#等价物的信息 - 例如STIntersects
。