CREATE TABLE HOUSE(
HOUSE_NAME VARCHAR2(255),
OWNER_ID VARCHAR2(255),
PRIMARY KEY(FOLDER_NAME, USER_ID)
);
CREATE TABLE PET(
HOUSE_NAME VARCHAR2(255) NOT NULL,
OWNER_ID VARCHAR2(255) NOT NULL,
PET_NAME VARCHAR2(255) NOT NULL
);
ALTER TABLE PET
ADD CONSTRAINT FK_PET_HOUSE
FOREIGN KEY(HOUSE_NAME, OWNER_ID)
REFERENCES HOUSE(HOUSE_NAME, OWNER_ID)
ON DELETE CASCADE;
INSERT INTO HOUSE VALUES('House 1', 'Owner 1');
INSERT INTO HOUSE VALUES('House 2', 'Owner 1');
INSERT INTO HOUSE VALUES('House 3', 'Owner 1');
INSERT INTO PET VALUES('House 1', 'Owner 1', 'Dog');
INSERT INTO PET VALUES('House 1', 'Owner 1', 'Cat');
INSERT INTO PET VALUES('House 2', 'Owner 1', 'Duck');
INSERT INTO PET VALUES('House 3', 'Owner 1', 'Bird');
正如您所看到的,我在"HOUSE"
表中使用了复合键。我想要的是从DB得到3个这样的对象:
Owner Id: Owner1
House name: House 1
Pets: [Dog, Cat]
Owner Id: Owner1
House name: House 2
Pets: [Duck]
Owner Id: Owner1
House name: House 3
Pets: [Bird]
我一直在寻找一种方法,但我不知道如何链接这些表来检索列表。到目前为止我所拥有的是:
@Entity
@Table(name="HOUSE")
@SecondaryTable(name="PET", pkJoinColumns={
@PrimaryKeyJoinColumn(name="HOUSE_NAME", referencedColumnName="HOUSE_NAME"),
@PrimaryKeyJoinColumn(name="OWNER_ID", referencedColumnName="OWNER_ID"),
})
public class HousePets implements Serializable {
@Id
@Column(name="HOUSE_NAME")
private String houseName;
@Id
@Column(name="OWNER_ID")
private String ownerId;
@Column(table="PET" name="PET_NAME") //DON'T REALLY KNOW HOW TO DEAL WITH IT
private Set<String> petsSet = new HashSet<String>
//GETTERS AND SETTERS
}
要检索列表,我正在使用类似这样的方法:
public List<HousePets> getFoldersList() {
em = emf.createEntityManager();
Query q = em.createQuery("SELECT h FROM HousePets h WHERE h.ownerId = :ownerId");
q.setParameter("ownerId", "Owner 1");
List<HousePets> result = q.getResultList();
return result;
}
谢谢你的时间!
答案 0 :(得分:0)
你的模型毫无意义。 SecondaryTable不能是OneToMany关系。
你需要的是一个OWNER表,它定义了OWNER_ID,(可能是一个名字等)
所有者会有一个OneToMany到Pet,OneToOne(或ManyToOne,OneToMany?)到House
Pet将拥有ManyToOne给所有者和ManyToOne到House
House会有一个OneToMany到Pet和OneToMany吗?对所有者
要获得一个拥有者,您只需选择所有者,即可获取他们的宠物。