Question

我有一张包含以下细节的表格

ID    statusID  logTime
100238  1   2011-07-07 03:48:43.000
100238  2   2011-07-07 03:48:46.000
100238  1   2011-07-07 09:07:57.000
100238  2   2011-07-07 16:12:28.000
100238  1   2011-07-08 02:59:57.000
100238  2   2011-07-08 03:00:00.000
100238  1   2011-07-08 09:26:37.000
100238  2   2011-07-08 14:03:05.000

并且所需的输出应该像

repID   ClockIn                    ClockOut
100238  2011-07-07 03:48:43.000    2011-07-07 03:48:46.000
100238  2011-07-07 09:07:57.000    2011-07-07 16:12:28.000
100238  2011-07-08 02:59:57.000    2011-07-08 03:00:00.000
100238  2011-07-08 09:26:37.000    2011-07-08 14:03:05.000

ie ..如果statusID为1，则logtime必须在ClockIn列中，如果statusID为2，则logtime必须在ClockOut列中

我使用了像

这样的查询

SELECT repID,
       ClockIn,
       ClockOut from
  (SELECT a.eventID, 
          a.repID, 
          a.logTime, 
          CASE WHEN a.statusID = 1 THEN a.logTime ELSE NULL END AS ClockIn, 
          CASE WHEN b.statusID = 2 THEN b.logTime ELSE NULL END AS ClockOut
   FROM tbl_ets_reptimelog a
   LEFT JOIN tbl_ets_reptimelog b ON a.repID = b.repID)c

，结果如

repID   ClockIn                     ClockOut
100238  2011-07-07 03:48:43.000     NULL
100238  2011-07-07 03:48:43.000     2011-07-07 03:48:46.000
100238  2011-07-07 09:07:57.000     NULL
100238  2011-07-07 09:07:57.000     2011-07-07 16:12:28.000
100238  2011-07-08 02:59:57.000     NULL
100238  2011-07-08 02:59:57.000     2011-07-08 03:00:00.000
100238  2011-07-08 09:26:37.000     NULL
100238  2011-07-08 09:26:37.000     2011-07-08 14:03:05.000

如何删除在ClockOut Column

中使用NULL值显示的额外行

请帮助摆脱这个问题......

Answer 1

只需在外部查询

中添加WHERE子句即可

select repID,ClockIn,ClockOut from(select a.eventID, a.repID, a.logTime, 
case when a.statusID = 1 then a.logTime else null end as ClockIn,  
case when b.statusID = 2 then b.logTime else null end as ClockOut from tbl_ets_reptimelog a 
left join tbl_ets_reptimelog b on a.repID = b.repID)c
WHERE ClockOut IS NOT NULL

Answer 2

此查询应返回您需要的结果：

SELECT
  t1.ID,
  t1.logTime check_in,
  CASE WHEN MIN(t2.logTime) < MIN(t3.logTime) OR MIN(t3.logTime) IS NULL
       THEN MIN(t2.logTime) END check_out
FROM
  Logs t1 LEFT JOIN Logs t2
  ON t1.ID = t2.ID
     AND t2.statusID=2
     AND t1.logTime<t2.logTime
  LEFT JOIN Logs t3
  ON t2.ID = t3.ID
     AND t3.statusID=1
     AND t1.logTime<t3.logTime
WHERE
  t1.statusID=1
GROUP BY
  t1.ID, t1.logTime

请参阅小提琴here。

使用sql查询从Single Column设置两个列值

2 个答案: