Question

我在运行以下代码时遇到错误“找不到列”，即使该列存在于我的表中。我正在使用访问数据库，请求帮助

public class Trial1 {
public static void main (String[]args){

            try{
                Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");  
                String url = "jdbc:odbc:SENSOR";
                String user = "";
                String pass = "";
                Connection con = DriverManager.getConnection(url,user,pass);
                Statement stmt  = con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_UPDATABLE);                          //stmt代表資料庫連接成功


                ResultSet rs = stmt.executeQuery("select MAX(LevelNum) from NList");
                 if (rs.next()){

                    int w = rs.getInt("LevelNum");
                   int x= 3;                             

                double i = Math.pow(2, (w-x))-1;
                System.out.printf("i is  %f",i);}


                stmt.close();
                con.close();

            }catch(Exception e)
            {
                System.out.println("Error" + e);
            }

}

}

Answer 1

假设错误是在您获得结果而不是执行查询时，您可能需要这样的内容

// ...
ResultSet rs = stmt.executeQuery("select MAX(LevelNum) as maxLevel from NList");
if (rs.next())
{
    int w = rs.getInt("maxLevel");

    // ... etc.
}

Answer 2

试试这个......

class Trial1 {
public static void main (String[]args){

            try{
                Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");  
                String url = "jdbc:odbc:SENSOR";
                String user = "";
                String pass = "";
                Connection con = DriverManager.getConnection(url,user,pass);
                Statement stmt  = con.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_UPDATABLE);                          


                ResultSet rs = stmt.executeQuery("select MAX(LevelNum) as LEVELNUM from NList");
                 if (rs.next()){

                    int w = rs.getInt("LEVELNUM");
                   int x= 3;                             

                double i = Math.pow(2, (w-x))-1;
                System.out.printf("i is  %f",i);}


                stmt.close();
                con.close();

            }catch(Exception e)
            {
                System.out.println("Error" + e);
            }

}

Answer 3

如果您执行查询，它将返回表中可用的最大值，如果不存在记录，则返回空值列名 MAX(LevelNum) 而不是 LevelNum。

在您的代码中，您使用语句获取返回值

rs.getInt("LevelNum")

而您应该使用 MAX(LevelNum) 或使用别名-

SELECT MAX(LevelNum) AS MAX_NUM FROM NList

rs.getInt("MAX_NUM")

JDBC从Access表中选择Max值

3 个答案: