从表中选择几个max()

时间:2013-04-26 22:08:07

标签: sql sql-server-2008-r2 max

我首先要说的是(不幸的是)表结构。

我的目标是从查询中选择多个max()。可以说我有以下表格

          jobReferenceTable                     jobList
 jobID | jobName  | jobDepartment |        listID |  jobID  |
_______|__________|_______________|        _______|_________|
   1   | dishes   |   cleaning    |          1    |    1    |
   2   |vacumming |   cleaning    |          2    |    5    |
   3   | mopping  |   cleaning    |          3    |    2    |
   4   |countMoney|     admin     |          4    |    4    |
   5   | hirePpl  |     admin     |          5    |    1    |
                                             6    |    2    |
                                             7    |    3    |
                                             8    |    3    |
                                             9    |    1    |
                                             10   |    5    |

不知何故,我希望有一个查询从清理中选择jobID,然后显示每个作业的最新jobList ID。我在下面开始查询,下面是我希望得到的结果

查询

SELECT jrt.jobName, jrt.jobDepartment
FROM jobReferenceTable
WHERE jobDepartment = 'cleaning'
JOIN jobList jl ON jr.jobID = jl.jobID

结果

 jobName | jobDepartment | listID |
 ________|_______________|________|
    1    |    cleaning   |    9   |
    2    |    cleaning   |    6   |
    3    |    cleaning   |    8   |

1 个答案:

答案 0 :(得分:2)

试试这个;

SELECT jrt.jobName, jrt.jobDepartment, MAX(jl.listID)
FROM jobReferenceTable AS jrt INNER JOIN jobList AS jl ON jrt.jobID = jl.jobID
WHERE jrt.jobDepartment = 'cleaning'
GROUP BY jrt.jobName, jrt.jobDepartment

据我所知,您只需要MAX() - listID

MAX()是一个聚合函数,这意味着结果集的其余部分必须“分组”。