例如,
我想从。
创建一个函数对象mystr = \
"""
def foo(a=1):
print a
pass
"""
但是,使用compile(mystr)只会给我一个代码对象。我想拥有模块级函数对象,就像字符串是源代码的一部分一样。
这可以实现吗?
答案 0 :(得分:4)
exec mystr
将执行您提供的代码。
答案 1 :(得分:2)
是使用exec
:
>>> mystr = \
"""
def foo(a=1):
print a
pass
"""
>>> exec mystr
>>> foo
<function foo at 0x0274F0F0>
答案 2 :(得分:0)
您也可以在此使用compile
,它支持exec
,eval
,single
等模式:
In [1]: mystr = \
"""
def foo(a=1):
print a
pass
"""
...:
In [2]: c=compile(mystr,"",'single')
In [3]: exec c
In [4]: foo
Out[4]: <function __main__.foo>
compile
上的帮助:
In [5]: compile?
Type: builtin_function_or_method
String Form:<built-in function compile>
Namespace: Python builtin
Docstring:
compile(source, filename, mode[, flags[, dont_inherit]]) -> code object
Compile the source string (a Python module, statement or expression)
into a code object that can be executed by the exec statement or eval().
The filename will be used for run-time error messages.
The mode must be 'exec' to compile a module, 'single' to compile a
single (interactive) statement, or 'eval' to compile an expression.
The flags argument, if present, controls which future statements influence
the compilation of the code.
The dont_inherit argument, if non-zero, stops the compilation inheriting
the effects of any future statements in effect in the code calling
compile; if absent or zero these statements do influence the compilation,
in addition to any features explicitly specified.