我想打印枚举的文本值,如果我输入5,它将打印F1。如果我输入63,则必须打印H8。在下面的代码中,我尝试了cout<< “你选择了:”<< board_square(chosen_piece)<< endl,但它会打印两次值。
enum board_square {
A1 = 1, B1, C1, D1, E1, F1, G1, H1,
A2, B2, C2, D2, E2, F2, G2, H2,
A3, B3, C3, D3, E3, F3, G3, H3,
A4, B4, C4, D4, E4, F4, G4, H4,
A5, B5, C5, D5, E5, F5, G5, H5,
A6, B6, C6, D6, E6, F6, G6, H6,
A7, B7, C7, D7, E7, F7, G7, H7,
A8, B8, C8, D8, E8, F8, G8, H8,
};
int choose_piece()
{
using namespace std;
cout << "X Location?" << endl << ">";
int column;
cin >> column;
cout << "Y Location?" << endl << ">";
int line;
cin >> line;
//This formula calculates which square is placed on the dimensions you entered
int chosen_piece = (column + (line - 1) * 8);
return chosen_piece;
}
int main()
{
using namespace std;
cout << "Enter dimensions for the piece you want to move" << endl;
int chosen_piece = choose_piece();
cout << chosen_piece << endl;
//How can I get it to print the enum for it here?
cout << "You chose: " << board_square(chosen_piece) << endl; //This doesn't work either :(
return 0;
}
答案 0 :(得分:2)
您的运行时C ++可执行文件并非旨在了解您创建的所有符号的名称。
如果您遇到特定问题,生成匹配名称非常容易。
std::string name_of( board_square s )
{
std::string name;
name += 'A' + int(s) % 8; // First character
name += '1' + int(s) / 8; // Second character
return name;
}
答案 1 :(得分:1)
我想打印枚举的文本值
这不是简单的事情。我觉得这是一个XY问题。您可以做什么(假设字母表中的字母顺序排列的区域设置):
string name;
name += (char)(column + 'A');
name += (char)(line + '1');
cout << "You chose: " << name << endl;
答案 2 :(得分:1)
在运行时无法使用枚举器名称;它们只是一种方便的方式,可以为源中的数字命名。您将需要一些运行时代码将数值转换为运行时字符串,可能类似于:
std::string label(int row, int col) {
return {char('A'+row), char('1'+col)};
}