打印枚举文本而不是值C ++

Question

在Form.h中，我有：

enum Direction {
   NORTH = 0,
   SOUTH = 1,
   EAST = 2,
   WEST = 3,
};

在Play.cpp中我有一个方法可以打印出类似＆＃34; PlayerA移动到NORTH＆＃34;

的运动

void Play::printMove(Direction dir) {
   std::cout << this->getName() << " moved to " << dir << std::endl;
} 

因为这打印了0,1,2或3我尝试过：

void Play::printMove(Direction dir) {
   std::string moveStr;
   switch (dir) {
      case NORTH: moveStr = "NORTH";
      case SOUTH: moveStr = "SOUTH";
      case EAST: moveStr = "EAST";
      case WEST: moveStr = "WEST";
   }
   std::cout << this->getName() << " moved to " << moveStr << std::endl;
}

但这也没有奏效。为什么？我该怎么办？

Answer 1

您需要break关键字，否则printMove()将始终生成“WEST”。一旦计算机找到匹配的案例，它就会一直读取switch语句后面的代码。 break关键字告诉计算机停止阅读并在switch的结束括号后继续执行该程序。

void Play::printMove(Direction dir) {
    std::string moveStr;
    switch (dir) {
        case NORTH: 
            moveStr = "NORTH";
            break;
        case SOUTH:
            moveStr = "SOUTH";
            break;
        case EAST:
            moveStr = "EAST";
            break;
        case WEST: 
            moveStr = "WEST";
            break;
    }
    std::cout << this->getName() << " moved to " << moveStr << std::endl;
}