Question

我编写了一个javascript函数来获取一个数组作为参数，但是当我想访问数组的条目时总是会发生一个未定义的错误。

function putStringTwo(k){
var table=document.getElementById("st2");
var tbody=document.createElement("tbody");
tbody.setAttribute("id","2td2");


var sCell=new Array(12);
var sRow=new Array(12);

for(var i=0;i<12;i++){
    sCell[i]=document.createElement("td");
    sCell[i].setAttribute("name",k[i]);      //error happens here 
    sCell[i].innerHTML=k[i];
    sCell[i].setAttribute("id","two"+i);
}

for(var i=0;i<12;i++){
    sRow[i]=document.createElement("tr");
    sRow[i].appendChild(sCell[i]);
    tbody.appendChild(sRow[i]);
}
table.appendChild(tbody);
for(var i=0;i<12;i++)
    $('#two'+i).addClass("drag");


}

这是来电者：

//here is the part of  php code used for generate a javascript function
<?php
$counter=0;
$flag=array();
$numdatabasekey=12;
for($counter=1;$counter<=$numdatabasekey;$counter++)
    $flag[$counter]=0;
$counter=0;
while($counter<12){
    $number=rand(1,$numdatabasekey);
    if($flag[$number]==0){
        $keynum[$counter]=$number;
        $flag[$number]=1;
        $counter++;
    }
}
$keyword=array();
if(!($database=mysql_connect("mysql.comp.polyu.edu.hk","xxxxxxxxxxx","xxxxxxxxxx")))
    die("Unable to connect to database </body></html>");
if(!mysql_select_db("10821473d",$database))
    die("unable to open 10821473d database </body></html>");
for($counter=0;$counter<12;$counter++){ 
    $query="SELECT * FROM Keyword WHERE id=$keynum[$counter]";
    if(!($result=mysql_query($query,$database))){
        print("could not execute query <br/>");
        die(mysql_error()."</body></html>");
    }
    $row=mysql_fetch_row($result);
    $keyword[$counter]=$row[1];
}

mysql_close($database);

$javascript=<<<JS
    function putImageTwo(){

        var table=document.getElementById("tb2");
        var tbody=document.createElement("tbody");
        tbody.setAttribute("id","2td");
        var imageTag=new Array(12);
        var imageCell=new Array(12);
        var imageRow=new Array(4);
        var keyword=new Array(12);

        // 1 get key word from database 


JS;

        for($i=0;$i<12;$i++){
            $javascript.="keyword[$i]='$keyword[$i]';";
        }
        $javascript.=<<<JS

        putStringTwo(keyword);

源 http://masqueradeljb.bugs3.com/Q3frame.php

k或关键字的内容：（12个字符串） “南丫岛” “HarborCity” “长洲岛” “香港大学” “杜莎夫人蜡像馆 ” ....

未捕获的TypEerror：无法读取未定义的属性“0”

0 个答案: