我想使用java读取一个名为(results.json)的.json文件,并通过键'title'提取数组的值。
这是我的.json文件
[
{
"title": {
"0": "UNIQUE SIGNED HARRY POTTER DELUXE VOLUME SALESMAN DUMMY"
}
},
{
"title": {
"0": "Harry Potter and the Philosopher's Stone by JK Rowling - Uncorrected Proof/ARC!!"
}
},
{
"title": {
"0": "Huge Lego Lot 532 Lbs Pounds Legos Star Wars Castle Harry Potter City Minifigs"
}
}
]
这是我正在使用的java代码
public class JJ {
public static void main(String[] args)
{
readJsonFile();
}
public static void readJsonFile() {
BufferedReader br = null;
JSONParser parser = new JSONParser();
try {
String sCurrentLine;
br = new BufferedReader(new FileReader("C:/wamp/www/epsilon/results.json"));
while ((sCurrentLine = br.readLine()) != null) {
System.out.println("Names of the Books:\t" + sCurrentLine);
Object obj;
try {
obj = parser.parse(sCurrentLine);
JSONObject jsonObject = (JSONObject) obj;
String name = (String) jsonObject.get("title");
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
我收到错误说
线程“main”中的异常java.lang.ClassCastException:org.json.simple.JSONArray无法强制转换为org.json.simple.JSONObject。
答案 0 :(得分:2)
这很简单。您的Json文件在顶层有一个数组。当JSonParser解析它时,它将它作为JSONArray返回。您正在尝试将其转换为JSONObject(这类似于地图或字典。)您需要做的是:
Object obj;
try {
obj = parser.parse(sCurrentLine);
JSONArray jsonArray = (JSONArray) obj;
for(obj : jsonArray){//not sure of the exact syntax, I don't have an IDE in front of me.
JSONObject jsonObject = (JSONObject)obj;
JSONObject realTitle = (JSONObject)jsonObject.get("0");
String name = (String) realTitle.get("title");
}
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
答案 1 :(得分:1)
Object obj = parser.parse(new FileReader("/Users/path/to/file/file.txt"));
JSONArray jsonArray = (JSONArray) obj;
for (int i = 0; i < jsonArray.size(); i++) {
JSONObject jsonObjectRow = (JSONObject) jsonArray.get(i);
String name = (String) jsonObjectRow.get("Name");
String address = (String) jsonObjectRow.get("Address");
Long telephone = (Long) jsonObjectRow.get("Phone_Number");
}
答案 2 :(得分:-2)
我有同样的问题,解决它只是替换它:
obj = parser.parse(sCurrentLine);
JSONObject jsonObject = (JSONObject) obj;
由:
obj = parser.parse(sCurrentLine);
JSONObject jsonObject = new JSONObject((parser.parse(sCurrentLine)).toString());