SQL嵌套聚合查询 - 如何获得每位员工的客户数量?

时间:2013-04-17 21:30:14

标签: sql sql-server-2008 subquery

以下是我需要回答的提示:

列出每位员工的客户数量。包括员工的姓名和人数 客户贴上标签,首先列出员工最多的客户。

以下是我的EMPLOYEES表:

create table EMPLOYEES
    (EmpID    char(4)         unique Not null,
     Ename    varchar(10),
     Job      varchar(9),
     MGR      char(4),
     Hiredate date,
     Salary   decimal(7,2),
     Comm     decimal(7,2),
     DeptNo   char(2)         not null,
         Primary key(EmpID),
         Foreign key(DeptNo) REFERENCES DEPARTMENTS(DeptNo));


insert into EMPLOYEES values (7839,'King','President',null,'17-Nov-11',5000,null,10);
insert into EMPLOYEES values (7698,'Blake','Manager',7839,'01-May-11',2850,null,30);
insert into EMPLOYEES values (7782,'Clark','Manager',7839,'02-Jun-11',2450,null,10);
insert into EMPLOYEES values (7566,'Jones','Manager',7839,'02-Apr-11',2975,null,20);
insert into EMPLOYEES values (7654,'Martin','Salesman',7698,'28-Feb-12',1250,1400,30);
insert into EMPLOYEES values (7499,'Allen','Salesman',7698,'20-Feb-11',1600,300,30);
insert into EMPLOYEES values (7844,'Turner','Salesman',7698,'08-Sep-11',1500,0,30);
insert into EMPLOYEES values (7900,'James','Clerk',7698,'22-Feb-12',950,null,30);
insert into EMPLOYEES values (7521,'Ward','Salesman',7698,'22-Feb-12',1250,500,30);
insert into EMPLOYEES values (7902,'Ford','Analyst',7566,'03-Dec-11',3000,null,20);
insert into EMPLOYEES values (7369,'Smith','Clerk',7902,'17-Dec-10',800,null,20);
insert into EMPLOYEES values (7788,'Scott','Analyst',7566,'09-Dec-12',3000,null,20);
insert into EMPLOYEES values (7876,'Adams','Clerk',7788,'12-Jan-10',1100,null,20);
insert into EMPLOYEES values (7934,'Miller','Clerk',7782,'23-Jan-12',1300,null,10);

以下是我的CUSTOMERS表:

create table CUSTOMERS
    (CustID      char(6)       unique Not null,
     Name        varchar(45),
     Address     varchar(40),
     City        varchar(30),
     State       varchar(2),
     Zip         varchar(9),
     AreaCode    char(3),
     Phone       varchar (9),
     RepID       char(4)       not null,
     CreditLimit decimal(9,2),
     Primary key(CustID),
         Foreign key(RepID) References EMPLOYEES(EmpID));


insert into CUSTOMERS values (100,'Jocksports','345 Viewridge','Belmont','CA','96711',415,'598-6609',7844,5000);
insert into CUSTOMERS values (101,'TKB Sport Shop','490 Boli Rd.','Redwood City','CA','94061',415,'368-1223',7521,10000);
insert into CUSTOMERS values (102,'Vollyrite','9722 Hamilton','Burlingame','CA','95133',415,'644-3341',7654,7000);
insert into CUSTOMERS values (103,'Just Tennis','Hillview Mall','Burlingame','CA','97544',415,'677-9312',7521,3000);
insert into CUSTOMERS values (104,'Every Mountain','574 Surry Rd.','Cupertino','CA','93301',408,'996-2323',7499,10000);
insert into CUSTOMERS values (105,'K + T Sports','3476 El Paseo','Santa Clara','CA','91003',408,'376-9966',7844,5000);
insert into CUSTOMERS values (106,'Shape Up','908 Sequoia','Palo Alto','CA','94301',415,'364-9777',7521,6000);
insert into CUSTOMERS values (107,'Womens Sports','Valco Village','Sunnyvale','CA','93301',408,'967-4398',7499,10000);
insert into CUSTOMERS values (108,'North Woods Fitness Supply Center','98 Lone Pine Way','Hibbing','MN','55649',612,'566-9123',7844,8000);

以下是我的疑问:

select ename, empId
from EMPLOYEES
where EmpID in
(select count(repid) as NumberOfCustomers
from CUSTOMERS
group by RepID);

为什么我的查询不起作用?

我知道我希望将来自EMPLOYEES的empid与CUSTOMERS中的repID相匹配,然后计算代表ID在CUSTOMERS中显示的次数。我需要EMPLOYEES表的唯一原因是输出Ename。我混淆了我需要使用的语法,因为我需要在CUSTOMERS表中输出RepID的数量

4 个答案:

答案 0 :(得分:1)

SELECT  *
FROM    employees e
CROSS APPLY
        (
        SELECT  COUNT(*)
        FROM    customers c
        WHERE   c.repId = e.empId
        ) cc (cnt)
ORDER BY
        cnt DESC

SQLFiddle

上查看

与子查询相同:

SELECT  *,
        (
        SELECT  COUNT(*)
        FROM    customers c
        WHERE   c.repId = e.empId
        ) cnt
FROM    employees e
ORDER BY
        cnt DESC

答案 1 :(得分:1)

如果您使用Common Table Expression及更高版本,也可以使用SQL Server 2005

;WITH CTE
AS
(
   SELECT RepID, COUNT(*) AS CNT
   FROM CUSTOMERS 
   GROUP BY REPID  
)

SELECT E.Ename, E.EmpID, ISNULL(C.CNT, 0) 
FROM EMPLOYEES E
LEFT OUTER JOIN CTE C ON C.RepID = E.EmpID

DEMO

答案 2 :(得分:0)

您的内部查询只有count(repid),这是一个计数,而不是外部查询在where EmpID in (xxx)中需要的实际EmployeeID。不确定为什么你想要在你的内部查询中计数,因为你会在最终结果中丢失它,但这应该有效:

 select ename, empId
 from EMPLOYEES
 where EmpID in (
    select repID
    from CUSTOMERS);

答案 3 :(得分:0)

这个怎么样?还是我误解了

 SELECT ename, count(*) as NumCustomers 
FROM Customers INNER JOIN 
 Employees ON customers.repid = employees.empid GROUP BY repid,ename 
 ORDER BY numCustomers DESC