Question

我正在使用MSSQL server 2008并有两个表forms和employees。

forms包含员工填写的所有表格，例如

[id][employeeId][formId]

只有6种类型的表单，每种表单都有自己的ID。如何构建查询以列出每种类型的表单以及它们是否已完成（存在于forms表中），例如

。

[employeeId][formType1][formType2][formType3]...
 1           1          null       1
 2           1          1          null

编辑：我当前的查询列出了所有需要“过滤”到上面架构的信息：

SELECT  *
FROM forms as f
inner join employees as e on e.EmployeeID = f.EmployeeID

Answer 1

您可以按员工ID进行分组，并“计算”每种表单类型的实例数：

SELECT  employeeid,
    SUM(CASE WHEN f.ID = 1 THEN 1 ELSE 0 END) formType1,
    SUM(CASE WHEN f.ID = 2 THEN 1 ELSE 0 END) formType2,
    SUM(CASE WHEN f.ID = 3 THEN 1 ELSE 0 END) formType3,
    SUM(CASE WHEN f.ID = 4 THEN 1 ELSE 0 END) formType4,
    SUM(CASE WHEN f.ID = 5 THEN 1 ELSE 0 END) formType5,
    SUM(CASE WHEN f.ID = 6 THEN 1 ELSE 0 END) formType6
FROM forms as f
GROUP BY employeeid

Answer 2

也许这可以解决问题

SELECT emp.[employeeName], form1.formId as formType1, form2.formId as formType2, form3.formId as formType3, form4.formId as formType4, form5.formId as formType5, form6.formId as formType6 
FROM [database_name].dbo.[employees] as emp 
RIGHT OUTER JOIN [database_name].dbo.[form] as form1 ON (emp.[EmployeeID] = form1.[EmployeeID] AND form1.id='ID_FOR_THE_FORM1') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form2 ON (emp.[EmployeeID] = form2.[EmployeeID] AND form2.id='ID_FOR_THE_FORM2') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form3 ON (emp.[EmployeeID] = form3.[EmployeeID] AND form3.id='ID_FOR_THE_FORM3') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form4 ON (emp.[EmployeeID] = form4.[EmployeeID] AND form4.id='ID_FOR_THE_FORM4') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form5 ON (emp.[EmployeeID] = form5.[EmployeeID] AND form5.id='ID_FOR_THE_FORM5') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form6 ON (emp.[EmployeeID] = form6.[EmployeeID] AND form6.id='ID_FOR_THE_FORM6') ;

不完全是你在寻找什么你可以评估是否为NULL然后员工没有回答那个形成他回答的所有其他内容。我希望这有帮助

Answer 3

如果您希望看到那些没有填写任何表格的员工，那么您可以试试这个：

Select FormName, EmpName, id
FROM 
    (SELECT formID ,FormName , empID, EmpName
            FROM FormTypes  
                CROSS JOIN Emp) x
        LEFT JOIN Forms f on (x.empid = f.employeename and  x.formID = f.formID)

SQL查询为每个员工选择每种类型的表单

3 个答案: