我在LinkList.java中遇到错误,在“curr.names.length() - 1”中。 .length是一个错误。我该如何解决?这里仍然是新的,我并不太了解Java。只是想我会试一试。这是我得到的代码:
SinglyNode.java
public class SinglyNode
{
public Object names;
public SinglyNode next;
public SinglyNode (Object name1)
{
names = name1;
next = null;
}
public void setNext(SinglyNode next1)
{
next = next1;
}
Object getObject()
{
return names;
}
SinglyNode getNext()
{
return next;
}
void displayLink()
{
System.out.print("{" + names + "}");
}
}
LinkList.java 错误在这里
public class LinkList
{
SinglyNode first;
SinglyNode last;
public boolean isEmpty()
{
return (first == null);
}
void insertFirst(Object name1)
{
SinglyNode newNode1 = new SinglyNode(name1);
newNode1.next = first;
first = newNode1;
}
void display()
{
SinglyNode current = first;
while(current != null)
{
current.displayLink(); // print data
current = current.next; // move to next link
}
System.out.println("\n");
}
public void bubbleSort()
{
int length = 0;
SinglyNode hold = first;
while(true)
{
if(hold == last)
{
break;
}
hold = hold.next;
length++;
}
while(true)
{
if(length == 0)
{
break;
}
int i = 0;
SinglyNode curr = first;
while(true)
{
if(i == length)
{
break;
}
if( curr.names.charAt(curr.names.length()-1) >
curr.next.names.charAt(curr.next.names.length()-1))
{
swap(curr);
}
curr = curr.next;
i++;
}
length--;
}
}
private void swap(SinglyNode node)
{
Object temp = node.names;
node.names = node.next.names;
node.next.names = temp;
}
}
这是主要课程 MainApp.java
ppublic class MainApp
{
public static void main (String args[])
{
LinkList list = new LinkList();
list.insertFirst("Squirtle");
list.insertFirst("Bulbasaur");
list.insertFirst("Charmander");
list.insertFirst("Pichu");
list.insertFirst("Ghastly");
list.insertFirst("Mewtwo");
list.insertFirst("Dialga");
System.out.println("LIST: ");
list.display();
System.out.println("BUBBLE SORT: ");
list.bubbleSort();
list.display();
}
}
答案 0 :(得分:0)
Object
没有length()
方法 - 您只能使用相应的方法签名在类上调用.length()
。你有意这是String
吗?如果是,请将您的代码更改为public String names
,public SinglyNode(String name1)
和String getObject()
(或String getName()
或String getString()
)