Question

我有这个查询，它为'stats'表添加了一大堆值。查询运行时，它选择要在子查询中填充表的值。我想知道这是否可以更有效率，或者我做错了什么。我对MySQL并不熟悉所以任何帮助都会很棒：）

以下是查询：

UPDATE mediastats SET 
    mediastats_members = (SELECT count(*) FROM status WHERE status_media_id = :id),
    mediastats_avscore = (SELECT AVG(status_rating) FROM status WHERE status_media_id = :id),
    mediastats_done = (SELECT count(*) FROM status WHERE status_status = 'done' AND status_media_id = :id),
    mediastats_doing = (SELECT count(*) FROM status WHERE status_status = 'doing' AND status_media_id = :id),
    mediastats_redoing = (SELECT count(*) FROM status WHERE status_status = 'redoing' AND status_media_id = :id),
    mediastats_dropped = (SELECT count(*) FROM status WHERE status_status = 'dropped' AND status_media_id = :id),
    mediastats_wantto = (SELECT count(*) FROM status WHERE status_status = 'wantto' AND status_media_id = :id),
    mediastats_wont = (SELECT count(*) FROM status WHERE status_status = 'wont' AND status_media_id = :id),
    mediastats_stalled = (SELECT count(*) FROM status WHERE status_status = 'stalled' AND status_media_id = :id),
    mediastats_rating_1 = (SELECT count(*) FROM status WHERE status_rating = 1 AND status_media_id = :id),
    mediastats_rating_2 = (SELECT count(*) FROM status WHERE status_rating = 2 AND status_media_id = :id),
    mediastats_rating_3 = (SELECT count(*) FROM status WHERE status_rating = 3 AND status_media_id = :id),
    mediastats_rating_4 = (SELECT count(*) FROM status WHERE status_rating = 4 AND status_media_id = :id),
    mediastats_rating_5 = (SELECT count(*) FROM status WHERE status_rating = 5 AND status_media_id = :id),
    mediastats_rating_6 = (SELECT count(*) FROM status WHERE status_rating = 6 AND status_media_id = :id),
    mediastats_rating_7 = (SELECT count(*) FROM status WHERE status_rating = 7 AND status_media_id = :id),
    mediastats_rating_8 = (SELECT count(*) FROM status WHERE status_rating = 8 AND status_media_id = :id),
    mediastats_rating_9 = (SELECT count(*) FROM status WHERE status_rating = 9 AND status_media_id = :id),
    mediastats_rating_10 = (SELECT count(*) FROM status WHERE status_rating = 10 AND status_media_id = :id)
    WHERE mediastats_media_id = :id

：从PHP添加id。

Answer 1

以下是我在PHP中使用PDO的方法：

$sql = "
    SELECT
     COUNT(*) AS mediastats_members,
     AVG(status_rating) AS mediastats_avscore,
     SUM(status_status = 'done') AS mediastats_done,
     SUM(status_status = 'doing') AS mediastats_doing,
     SUM(status_status = 'redoing') AS mediastats_redoing,
     SUM(status_status = 'dropped') AS mediastats_dropped,
     SUM(status_status = 'wantto') AS mediastats_wantto,
     SUM(status_status = 'wont') AS mediastats_wont,
     SUM(status_status = 'stalled') AS mediastats_stalled,
     SUM(status_rating = 1) AS mediastats_rating_1,
     SUM(status_rating = 2) AS mediastats_rating_2,
     SUM(status_rating = 3) AS mediastats_rating_3,
     SUM(status_rating = 4) AS mediastats_rating_4,
     SUM(status_rating = 5) AS mediastats_rating_5,
     SUM(status_rating = 6) AS mediastats_rating_6,
     SUM(status_rating = 7) AS mediastats_rating_7,
     SUM(status_rating = 8) AS mediastats_rating_8,
     SUM(status_rating = 9) AS mediastats_rating_9,
     SUM(status_rating = 10) AS mediastats_rating_10
    FROM status
    WHERE status_media_id = :id";
$stmt = $pdo->prepare($sql);
$stmt->execute(array("id"=>$id));
$params = $stmt->fetch(PDO::FETCH_ASSOC);

这样，您可以在表的一次传递中计算所有聚合，而不是为每个计数使用单独的子查询。

我正在使用MySQL的技巧 - 布尔表达式的SUM（）等于表达式为真的COUNT（）。这是因为MySQL布尔表达式总是返回0或1，而0和1的SUM等于1的COUNT。

然后，您可以将上述查询的结果用作UPDATE语句的参数数组：

$sql = "
    UPDATE mediastats SET 
        mediastats_members = :mediastats_members,
        mediastats_avscore = :mediastats_avscore,
        mediastats_done = :mediastats_done,
        mediastats_doing = :mediastats_doing,
        mediastats_redoing = :mediastats_redoing,
        mediastats_dropped = :mediastats_dropped,
        mediastats_wantto = :mediastats_wantto,
        mediastats_wont = :mediastats_wont,
        mediastats_stalled = :mediastats_stalled,
        mediastats_rating_1 = :mediastats_rating_1,
        mediastats_rating_2 = :mediastats_rating_2,
        mediastats_rating_3 = :mediastats_rating_3,
        mediastats_rating_4 = :mediastats_rating_4,
        mediastats_rating_5 = :mediastats_rating_5,
        mediastats_rating_6 = :mediastats_rating_6,
        mediastats_rating_7 = :mediastats_rating_7,
        mediastats_rating_8 = :mediastats_rating_8,
        mediastats_rating_9 = :mediastats_rating_9,
        mediastats_rating_10 = :mediastats_rating_10
    WHERE mediastats_media_id = :id";

$stmt = $pdo->prepare($sql);
$params["id"] = $id;
$stmt->execute($params);

自PHP 5.3.4起，PDO接受没有前导:的参数数组键。在查询中声明参数占位符时需要冒号，但在为execute（）提供的值数组中不需要冒号。

Answer 2

UPDATE  (
        SELECT  status_media_id,
                COUNT(*) AS cnt, AVG(status_rating) AS avg_rating,
                SUM(status_status = 'done') AS cnt_done,
                ...
        FROM    status
        WHERE   status_media_id = :id
        ) s
JOIN    mediastats ms
ON      ms.mediastats_media_id = s.status_media_id
SET     ms.mediastats_members = cnt,
        ms.mediastats_avscore = avg_rating,
        ms.mediastats_done = cnt_done,
        ...

MySQL子查询效率

2 个答案: