Question

试图在Python中制作游戏..虽然我似乎无法获得某些代码的工作？！这让我疯了！

非常感谢任何帮助！

import random

die1 = random.randint(1,10)
die2 = random.randint(1,10)
die3 = random.randint(1,10)


if die1 > die2:
    print ('Die 1:', die2,'  Die 2:', die1,)
else:
    print ('Die 1:', die1,'  Die 2:', die2,)

    if die1 == die2 or die2 == die1:
        print('\nEven-steven!')
    else:
        print('\nNot the same, let\'s play!')

print ('\nDie 3:', die3,)



if die3 > die1 and die3 < die2 or die3 < die1 and die3 > die2: 
    print ('\n*** You win! ***')
elif die1 > die2:
    if die3 < die2 or die3 > die1:
        print('\n*** Sorry - You lose! ***')
elif die2 > die1:
    if die3 < die1 or die3 > die2:
        print('\n*** Sorry - You lose! ***')
**elif die3 == die1 or die3 == die2:
    print ('\n*** You hit the post - You lose double your bet! ***')**


print ('\nThanks for playing!')

它位于第二个if语句结构中，无论出于何种原因，如果die1或die2与die3相同，它就不会打印出“你点击帖子......”它只是结束了！

谢谢！

Answer 1

您的诊断不正确。如果die3等于die1或die2，的最后一个语句将匹配：

>>> die1, die2 = 1, 2
>>> die3 = die1
>>> die3 == die1 or die3 == die2
True
>>> die3 = die2
>>> die3 == die1 or die3 == die2
True

但是，如果die1大于die2您的第一个 elif匹配，但您与die3的比较存在缺陷：

>>> die1, die2 = 2, 1
>>> die3 = die1
>>> die3 < die2 or die3 > die1
False

打印

和没有。您需要清理该案例的逻辑。

因为你只有3种不同的结果;赢得，失败和击中帖子，你可以真正简化整个事情：

if die1 < die3 < die2:
    print('\n*** You win! ***')
elif die3 == die1 or die3 == die2:
    print('\n*** You hit the post - You lose double your bet! ***')
else:
    print('\n*** Sorry - You lose! ***')

请注意，我使用chained comparisons来简化第一个if表达式。您还确保die1低于die2，因此对die2 < die3 < die1的测试始终将为False。

另一个注意事项：==应该是可传递的，因此die1 == die2 or die2 == die1是多余的。您可以将其简化为die1 == die2。

简化整个计划：

import random

die1 = random.randint(1,10)
die2 = random.randint(1,10)

if die1 > die2:
    die1, die2 = die2, die1

print ('Die 1:', die1,'  Die 2:', die2,)

if die1 == die2:
    print('Even-steven!')
else:
    print("Not the same, let's play!")
    die3 = random.randint(1,10)

    print ('Die 3:', die3)

    if die1 < die3 < die2:
        print('\n*** You win! ***')
    elif die3 == die1 or die3 == die2:
        print('\n*** You hit the post - You lose double your bet! ***')
    else:
        print('\n*** Sorry - You lose! ***')

print ('Thanks for playing!')

Answer 2

不要让它疯狂，保持冷静，并使用pdb。

if die3 in (die1, die2):
    import pdb; pdb.set_trace()

if die3 > die1 and die3 < die2 or die3 < die1 and die3 > die2: 
    print ('\n*** You win! ***')
elif die1 > die2:
    if die3 < die2 or die3 > die1:
        print('\n*** Sorry - You lose! ***')
elif die2 > die1:
    if die3 < die1 or die3 > die2:
        print('\n*** Sorry - You lose! ***')
**elif die3 == die1 or die3 == die2:
    print ('\n*** You hit the post - You lose double your bet! ***')**


print ('\nThanks for playing!')

现在运行它，当它运行时，开始调试（使用n进行下一步，检查每个条件的值等）。

Answer 3

通过简化代码，调试起来会容易得多。只有3个条件win，lose或lose (double)，因此不需要6个（嵌套）条件。如果die1您的程序输出和变量保持有意义，也可以切换die2和die1 > die2。这是更健全的：

import random

die1 = random.randint(1,10)
die2 = random.randint(1,10)

if die1 > die2:
    die1, die2 = die2, die1

print('Die 1:',die1,'Die 2:',die2)

if die1 == die2:
    print('Even-steven!')
else:
    print("Not the same, let's play!")  

    die3 = random.randint(1,10) 
    print('Die 3:',die3)

    if die3 > die1 and die3 < die2 or die3 < die1 and die3 > die2: 
        print ('You win!')
    elif die3 == die1 or die3 == die2:
        print ('You hit the post - You lose double your bet!')
    else:
        print('Sorry - You lose!')

print('Thanks for playing!')

Answer 4

最终if语句的elif仅作为第3个条件的内部if语句的替代解决方案的一部分进行处理。

以下内容应该可以解决您的问题。请注意更改

if die3 > die1 and die3 < die2 or die3 < die1 and die3 > die2: 
    print ('\n*** You win! ***')
elif die1 > die2 and (die3 < die2 or die3 > die1):
    print('\n*** Sorry - You lose! ***')
elif die2 > die1 and (die3 < die1 or die3 > die2):
    print('\n*** Sorry - You lose! ***')
elif (die3 == die1) or (die3 == die2):
    print ('\n*** You hit the post - You lose double your bet! ***')

享受。：）

Answer 5

这个怎么样？

if die3 == die1 or die3 == die2:
    print ('\n*** You hit the post - You lose double your bet! ***')
else:
    if die3 > die1 and die3 < die2 or die3 < die1 and die3 > die2: 
        print ('\n*** You win! ***')
    elif die1 > die2:
        if die3 < die2 or die3 > die1:
            print('\n*** Sorry - You lose! ***')
    elif die2 > die1:
        if die3 < die1 or die3 > die2:
            print('\n*** Sorry - You lose! ***')

中间的Python游戏 - 无法让if-elif工作

5 个答案: