Question

这是通常的javascript，它会查找隐藏的元素。

   private RemoteWebElement getItemInSubmenu(WebElement parent, String itemName) {
        String script = "var el = jQuery(arguments[0].getElementsBySelector('div.rich-menu-list-bg>div.rich-menu-item>.rich-menu-item-label')).filter(function() {"
                + "return jQuery(this).text().trim() === '" + itemName + "'});"
                + "jQuery(el).parents('div.rich-menu-list-border:hide').show();"
                + "return el.get(0);";
        return (RemoteWebElement) browser.executeScript(script, parent);
    }

我想让它异步。如何实现回调？

Answer 1

这些是直接从Selenium JavaDoc中提取的，可以在这里找到：

http://selenium.googlecode.com/git/docs/api/java/index.html

示例＃1：在被测浏览器中执行休眠。

long start = System.currentTimeMillis();
((JavascriptExecutor) driver).executeAsyncScript("window.setTimeout(arguments[arguments.length - 1], 500);");
System.out.println("Elapsed time: " + System.currentTimeMillis() - start);

示例＃2：将测试与AJAX应用程序同步

WebElement composeButton = driver.findElement(By.id("compose-button"));
composeButton.click();
((JavascriptExecutor) driver).executeAsyncScript(
  "var callback = arguments[arguments.length - 1];" +
  "mailClient.getComposeWindowWidget().onload(callback);");
driver.switchTo().frame("composeWidget");
driver.findElement(By.id("to")).sendKeys("bog@example.com");

示例＃3：注入XMLHttpRequest并等待结果：

Object response = ((JavascriptExecutor) driver).executeAsyncScript(
    "var callback = arguments[arguments.length - 1];" +
    "var xhr = new XMLHttpRequest();" +
    "xhr.open('GET', '/resource/data.json', true);" +
    "xhr.onreadystatechange = function() {" +
    "  if (xhr.readyState == 4) {" +
    "    callback(xhr.responseText);" +
    "  }" +
    "}" +
    "xhr.send();");
JSONObject json = new JSONObject((String) response);
assertEquals("cheese", json.getString("food"));

在webDriver中执行异步脚本

1 个答案: